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1 year ago

What’s the scale factor? Please hurry I’m tired and sleep deprived help me I just don’t get it and I want sleep

Mathematics

1 answer:

Doss [256]1 year ago

7 0

In order to find the scale factor we begin by selecting one pair of corresponding sides.

Selecting the base of the triangle

Base of triangle AC is 3 units.

Base of triangle (AC)' is 7.5 units

According to the proportion

$AB\cdot k=(AB)^{\prime}$

REPLACE TH

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Final numeric grades in a certain course are normally distributed with a mean of 72.3 and a standard deviation of 6.4. The profe

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The minumum numeric grade you have to earn to obtain an A is 81.29.

Step-by-step explanation:

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In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 72.3, \sigma = 6.4$

The professor curves the grades so that the top 8% of students will receive an A. What is the minumum numeric grade you have to earn to obtain an A?

The minimum numeric value is the value of X when Z has a pvalue of 1-0.08 = 0.92. So it is X when Z = 1.405.

$Z = \frac{X - \mu}{\sigma}$

$1.405 = \frac{X - 72.3}{6.4}$

$X - 72.3 = 1.405*6.4$

$X = 81.29$

The minumum numeric grade you have to earn to obtain an A is 81.29.

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3 years ago

n automatic machine in a manufacturing process is operating properly if the lengths of an important subcomponent are normally di

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Answer:

0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.

Step-by-step explanation:

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Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.

This means that $\mu = 116, \sigma = 5.4$