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patriot [66]
3 years ago
14

Imagine a universe in which, like in ours, there are two kinds of charges (positive and negative), with the like charges repelli

ng and unlike charges attracting each other, but with the electric force somewhat different from Coulomb's Law. Instead of varying with inverse distance squared, the force between charges in this imagined world would vary with the inverse distance cubed. In such a universe, would the static charges still always be distributed on the surfaces of conductors?
Physics
1 answer:
GuDViN [60]3 years ago
5 0

Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

       F = k' \frac{q_1 q_2 }{r^2}

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

         F₀ = k \frac{q_1 q_2 }{r^2}

assuming the constant k is the same

the relationship between the two forces is

        F / F₀ = 1 / r

        F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

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Sabe-se que um alqueire paulista equivale a 24200 metros quadrados. Uma chácara retangular tem um alqueire e mede 100m de frente
sattari [20]

Answer:

b = 242 m

Explanation:

A = 24200 m²

a = 100 m

b = ?

A seguinte fórmula é aplicada

A = a*b

⇒  b = A / a

⇒  b = (24200 m²) / (100 m)

⇒  b = 242 m

5 0
3 years ago
The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the
aksik [14]

Answer:

Option A

The drag force goes up by a factor of 4

Explanation:

Fact:

Drag force is directly proportional to the square of the velocity of a moving object

Therefore, when drag force pushes opposite to the motion as one rides a bicycle, the magnitude of drag force increases by a factor of 4

3 0
4 years ago
If an object moving at 5 m/s accelerates for 30 seconds at a rate of 2
klasskru [66]

Answer:

V=u + at

V= final velocity

U= Initial velocity

a= acceleration

t= time taken

V= 5 + 30*2

V=5+60

V=65m/s

Explanation:

4 0
3 years ago
To stretch a spring 8.00cm from its unstretched length, 16.0J of work must be done.A)What is the force constant of this spring?B
ad-work [718]

A) 5000 N/m

The force constant of the spring can be found by using the expression for the elastic potential energy stored in the spring (which is equal to the work done on it):

W=U=\frac{1}{2}kx^2

where

k is the spring constant

x is the stretching/compression of the spring

In this problem, we have

W = 16.0 J is the work done

x = 8.00 cm = 0.08 m is the stretching

Substituting into the formula and re-arranging it, we find

k=\frac{2W}{x^2}=\frac{2(16.0 J)}{(0.08 m)^2}=5000 N/m

B) 400 N

The magnitude of the force needed to stretch the spring by x = 8.00 cm = 0.08 m is given by Hook's law:

F=kx

where k=5000 N/m as we found previously. Substituting x=0.08 m, we find:

F=(5000 N/m)(0.08 m)=400 N

C) 4 J

The work done to compress the spring by x=4.00 cm=0.04 m is given by the same formula used for part A:

W=\frac{1}{2}kx^2

where in this case, k=5000 N/m and x=0.04 m. Substituting, we find

W=\frac{1}{2}(5000 N/m)(0.04 m)^2=4 J

D) 200 N

As we did in part B), the force needed to stretch this distance is given by Hook's law:

F=kx

where in this case, k=5000 N/m and x=0.04 m. Substituting, we find

F=(5000 N/m)(0.04 m)=200 N

8 0
3 years ago
Complete the following table with the appropriate units of measurement. Word bank: gram, meter, kelvin, liter, second, grams/cm3
lara31 [8.8K]

mass gram, time sec, temp kelvin, vol liter, dens grams/cm3

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4 years ago
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