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aliina [53]
3 years ago
5

If an object moving at 5 m/s accelerates for 30 seconds at a rate of 2

Physics
1 answer:
klasskru [66]3 years ago
4 0

Answer:

V=u + at

V= final velocity

U= Initial velocity

a= acceleration

t= time taken

V= 5 + 30*2

V=5+60

V=65m/s

Explanation:

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The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth
ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

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Also gravity also remains same for both liquids

So taking ratio of their respective pressures we have

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5 0
3 years ago
Which statement correctly describes the relationship between current, voltage, and resistance? If we
Salsk061 [2.6K]

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Explanation:

According to ohm's law, the relationship between voltage, resistance, and current is that current passing through a conductor is directly proportional to the voltage over resistance.

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6 0
3 years ago
Read 2 more answers
An electron experiences a magnetic force with a magnitude of 4.90×10−15 n when moving at an angle of 60.0 ∘ with respect to a ma
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Missing questions: "find the speed of the electron".

Solution:
the magnetic force experienced by a charged particle in a magnetic field is given by
F=qvB \sin \theta
where
q is the particle charge
v its velocity
B the magnitude of the magnetic field
\theta the angle between the directions of v and B.

Re-arranging the formula, we find:
v= \frac{F}{qB \sin \theta}
and by substituting the data of the problem (the charge of the electron is q=1.6 \cdot 10^{-19} C), we find the velocity of the electron:
v= \frac{F}{qB \sin \theta}= \frac{4.90 \cdot 10^{-15}N}{(1.6 \cdot 10^{-19}C)(3.70 \cdot 10^{-3} T)(\sin 60^{\circ})}=9.56 \cdot 10^6 m/s
4 0
3 years ago
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