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3 years ago

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Note: A maximum number of 4 points are available for this question. Part A is worth 1 point. Part B is worth 1 point. Part C is

worth 2 points.
At a children's archery camp, the percentage of target hits for different distances from the target was recorded for several participants. The data is shown in the scatter plot below.

Describe any patterns in the scatter plot, such as clustering, outliers, and association. State where these patterns occur.

1 answer:

vovikov84 [41]3 years ago

4 0

Answer:

There is a decreasing pattern the farther they are the less likely hit the target.

Step-by-step explanation:

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A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic

Ket [755]

Answer:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

Step-by-step explanation:

Data given and notation

$\bar X=5.25$ represent the sample mean

$s=3.98$ represent the sample standard deviation

$n=54$ sample size

$\mu_o =4.73$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:

Null hypothesis: $\mu =4.73$

Alternative hypothesis: $\mu \neq 4.73$

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

7 0

3 years ago

HEY GUYS I NEED THIS ANSWER NOW

Sergio [31]

Let

x-------> the number of fiction books

y-------> the number of nonfiction books.

we know that

$x+y=26$ -----> equation $1$

$x=y+12$

$x-y=12$ -----> equation $2$

Add equation $1$ and equation $2$

$x+y=26\\x-y=12\\ ------\\ 2x=38\\ x=38/2\\x=19\ fiction\ books$

<u>find the value of y</u>

$x+y=26$

$19+y=26$

$y=26-19=7\ nonfiction\ books$

therefore

<u>the answer is</u>

Part a) the number of fiction books is $19\ fiction\ books$

Part b) the number of nonfiction books is $7\ nonfiction\ books$

6 0

3 years ago

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