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jarptica [38.1K]
3 years ago
14

The double box plot shows the test scores for Miss Robinson's second and fourth period

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Answer: The second period class has the greater first quartile.

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B) 144kg in the ratio 1 3.5​
Vlada [557]
So you add 13+5=18

Then you do 144/18=8

8x13=104 8x5=40

104+40=144✅

Answer= 104 : 40
6 0
3 years ago
Wren has a 30% chance of being selected as the president of the school sports club and a 80% chance of being elected editor of t
SashulF [63]
Multiply the two probabilities together to get the answer. 3/10 ×8/10 = 24/100 or 24 %
3 0
3 years ago
Read 2 more answers
Kelly tells you that when variables are in the denominator, the equation one over two plus three over x equals three over four b
olasank [31]
1/2 + 3/x = 3/4
multiply everything by x
1/2x + 3 = 3/4x...subtract 1/2x from both sides
3 = 3/4x - 1/2x
3 = 3/4x - 2/4x
3 = 1/4x...multiply both sides by 4
4 * 3 = x
12 = x
8 0
3 years ago
If AA and BB are two disjoint events with P(A)=0.15P(A)=0.15 and P(B)=0.75P(B)=0.75, find the following probabilities:
zubka84 [21]

Answer:

a 0

b) 0.9

c) 0.85

d) 0.25

e) 0.1

f) 0.0375

Step-by-step explanation:

a)

As A and B are two disjoints events, then P(A and B) is

P(A and B)=0

b)

As A and B are two disjoints events, then P(A or B) is

P(A or B)=P(A)+P(B)

P(A or B)=0.15+0.75=0.9

c)

P(not A)=1-P(A)

P(not A)=1-0.15=0.85

d)

P(not B)=1-P(B)

P(not B)=1-0.75=0.25

e)

P(not (A or B))=1-P(A or B)

P(not (A or B))=1-0.9=0.1

f)

P(A and (not B))=P(A)*P(not B)

P(A and (not B))=0.15*0.25=0.0375

5 0
3 years ago
Hannah is flying a kite with a trying that is 60 feet long. If Patricia is standing directly below the kite and 16 feet away fro
Nataly_w [17]

Answer:

74.5°

Step-by-step explanation:

Hannah, the kite and Patricia form the vertices of a right-angled triangle with the hypotenuse side the length of the string L = 60 feet and adjacent side the distance between Hannah and Patricia = d = 16 feet.

Let the angle between the string and the sand be Ф.

By trigonometric ratios,

cosФ = adjacent/hypotenuse

= d/L

= 16 feet/60 feet

= 0.2667

Ф = cos⁻¹(0.2667)

= 74.53°

≅ 74.5°

So, he angle between the string and the sand is Ф = 74.5°

7 0
3 years ago
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