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Dimas [21]
3 years ago
12

Jus this one question pls

Mathematics
1 answer:
krok68 [10]3 years ago
8 0
This is what i have found when i searched up your question!!! hope this helps!!!

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Zoom in to see the question plzzz help!!!
kondor19780726 [428]

Answer:

\huge\boxed{\boxed{IV}}

Step-by-step explanation:

Given:

x>0

Which means

x is any number greater than 0 ig 1,2,3,4,5,7,9.......

y<0

Which means

y Is any number smaller than 0

ig -1,-2,-3,-4,-5.........

So according to the question

The coordinates are

(x,-y)

Therefore,

The points are located to Quadrant IV

6 0
3 years ago
Find the factors of 9q²-45pq+8q-40p
Elina [12.6K]

Answer:

(x−5y)(9x+8)

Step-by-step explanation:

9x^2−45yx+8x−40y

Do the grouping 9x^2−45yx+8x−40y=(9x^2−45yx)+(8x−40y), and factor out 9x in the first and 8 in the second group.

9x(x−5y)+8(x−5y)

Factor out common term x−5y by using distributive property.

(x−5y)(9x+8)

5 0
3 years ago
Help me please I need help on this question!!!!!
Liono4ka [1.6K]
The answer is b I think
5 0
2 years ago
In a G.P the 3rd term is 4 times the 1st term and the sum of the 2nd term and the 4th term is 30.find the common ratio,find the
STALIN [3.7K]

Answer:

the common ratio is either 2 or -2.

the sum of the first 7 terms is then either 765 or 255

Step-by-step explanation:

a geometric sequence or series of progression (these are the most common names for the same thing) means that every new term of the sequence is created by multiplying the previous term by a constant factor which is called the common ratio.

so,

a1

a2 = a1×f

a3 = a2×f = a1×f²

a4 = a3×f = a1×f³

the problem description here tells us

a3 = 4×a1

and from above we know a3 = a1×f².

so, f² = 4

and therefore the common ratio = f = 2 or -2 (we need to keep that in mind).

again, the problem description tells us

a2 + a4 = 30

a1×f + a1×f³ = 30

for f = 2

a1×2 + a1×2³ = 30

2a1 + 8a1 = 30

10a1 = 30

a1 = 3

for f = -2

a1×-2 + a1×(-2)³ = 30

-10a1 = 30

a1 = -3

the sum of the first n terms of a geometric sequence is

sn = a1×(1 - f^(n+1))/(1-f) for f <>1

so, for f = 2

s7 = 3×(1 - 2⁸)/(1-2) = 3×-255/-1 = 3×255 = 765

for f = -2

s7 = -3×(1 - (-2)⁸)/(1 - -2) = -3×(1-256)/3 = -3×-255/3 =

= -1×-255 = 255

4 0
2 years ago
A jar contains 8 4/9 pounds of jam. If Sam eats 3 2/5 pounds of the jam, how many pounds of jam remains in the jar?
zepelin [54]
\bf 8\frac{4}{9}\implies \cfrac{8\cdot 9+4}{9}\implies \cfrac{76}{9}&#10;\\\\\\&#10;3\frac{2}{5}\implies \cfrac{3\cdot 5+2}{5}\implies \cfrac{17}{5}\\\\&#10;-------------------------------\\\\&#10;\cfrac{76}{9}-\cfrac{17}{5}\impliedby \textit{let's use an LCD of 45}\implies \cfrac{5\cdot 76-9\cdot 17}{45}&#10;\\\\\\&#10;\cfrac{380-153}{45}\implies \cfrac{227}{45}\implies \boxed{5\frac{2}{45}}&#10;\\\\\\&#10;5\frac{2}{45}\implies \cfrac{5\cdot 45+2}{45}\implies \cfrac{227}{45}
5 0
3 years ago
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