3 years ago

Jus this one question pls

Mathematics

1 answer:

krok68 [10]3 years ago

8 0

This is what i have found when i searched up your question!!! hope this helps!!!

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which pair of ratios is equivalent 8:32 and 16:64 or 52:56 and 17:19 or 34:40 and 16:20 or 6:8 and 16:12 help immediately

choli [55]

As it a lowest one so you will have to double it It is 16:64

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2 years ago

One bus averages 55 mi/h and the other bus averages 45 mi/h. when will they be 400 mi. apart?

aliya0001 [1]

They will be 400 miles apart in 4 hours.

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2 years ago

Factor: d2 + 16dm + 64m2

lutik1710 [3]

Answer:

$(d + 8m)^2$

Step-by-step explanation:

$d^2 + 16dm + 64 m^2 = (d + 8m)^2$

3 0

3 years ago

Read 2 more answers

Translate this sentence into an equation. The product of Rick's height and 4 is 64 . Use the variable r to represent Rick's heig

777dan777 [17]

The equation is r x 4 = 64 , then you do 64 / 4 = 16. So 16 is ricks height.

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2 years ago

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet. After 7 minutes it is at a height of 590

Jet001 [13]

Let's assume

height of plane in feet =h

time in minutes =t

we are given

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet

so, we get one point as (5,6500)

After 7 minutes it is at a height of 5900 feet

so, we get another point as (7,5900)

we can use point slope form of line

$y-y_1=m(x-x_1)$

points as

(5,6500)

x1=5, y1=6500

(7,5900)

x2=7 , y2=5900

Calculation of slope(m):

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{5900-6500}{7-5}$

$m=-300$

Equation of line:

we can use formula

$y-y_1=m(x-x_1)$

we can plug values

$h-6500=-300(t-5)$

$h=-300t+8000$

Time of landing:

we can set h=0

and then we can solve for t

$h=-300t+8000=0$

$t=\frac{80}{3}min$ ..............Answer

5 0

3 years ago