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labwork [276]
3 years ago
13

Identify the common difference 10,20,30,40 ..

Mathematics
1 answer:
klio [65]3 years ago
8 0

Answer: 10

Step-by-step explanation:

Hello there, 10 is your common difference. the numbers consecutively go up 10. You can also check by doing the third term minus the second or the 4th minus the 3rd.

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Alina's softball coach writes the team's number of games played and number of wins on a board in the locker room as shown, but t
belka [17]

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4 0
3 years ago
If rs =3x + 1, st = 2x- 2 ,and rt = 64,find the value of x
stealth61 [152]
             rs + st = rt     Plug in the values
3x + 1 + 2x - 2 = 64   Combine like terms (1 and -2)
       3x -1 + 2x = 64   Combine like terms (3x and 2x)
            -1 + 5x = 64   Add 1 to both sides
                  5x = 65   Divide both sides by 5
                    x = 13
3 0
3 years ago
If a = (3-2√2) find the value of a4+ 1/a4 ​
FinnZ [79.3K]

Answer:

  1154

Step-by-step explanation:

Perhaps the easiest way to evaluate this numerical expression is to let a calculator do it. Alternatively, we can compute the value from a +1/a.

__

<h3>expression</h3>

Consider the square of a +1/a:

  (a +1/a)^2 = a^2 +2(a)(1/a) +1/a^2 = (a^2 +1/a^2) +2

This means ...

  a^2 +1/a^2 = (a +1/a)^2 -2

Similarly, using a^2 for 'a' in the above, we have ...

  a^4 +1/a^4 = (a^2 +1/a^2)^2 -2

<h3>numerical value</h3>

The value of a +1/a is ...

  a+\dfrac{1}{a}=3-2\sqrt{2}+\dfrac{1}{3-2\sqrt{2}}=(3-2\sqrt{2})+\dfrac{3+2\sqrt{2}}{3^2-(2\sqrt{2})^2}\\\\=(3-2\sqrt{2})+(3+2\sqrt{2})\\\\a+\dfrac{1}{a}=6

Then the value of a^2 +1/a^2 is 6^2 -2 = 34

and the value of a^4 +1/a^4 is 34^2 -2 = 1154

4 0
2 years ago
Questions are easy.................. ؛)
Snowcat [4.5K]

Answer:

x>90

Step-by-step explanation:

x/3>30

(x/3)*3>30*3

x>90

5 0
3 years ago
Read 2 more answers
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