Let l, t, b represent the numbers of lions, tigers, bears, respectively.
2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals
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The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
Each semiannual payment is (1/2)*.0545*$1000 = $27.25. There are 2*30 = 60 such payments in 30 years. After 6 payments, there will be 54 left.
a) The value of Tristan's bond is $1238.08
b) The value of Tristan's bond is $926.91
Answer:
-15
Step-by-step explanation:
-7p+10p-16=6p+36-7
3p-16=6p+29
3p-6p=29+16
-3p=45
p=45/-3
p=-15
Am not 100% sure but I think it’s A
Answer:
T' is at (-1,-8)
Step-by-step explanation:
When we translate down 4 units, we will subtract 4 from the y coordinate
T is at (-1,-4)
We need to subtract 4 from the y coordinate
T' is at (-1,-4-4)
T' is at (-1,-8)
