Sum of geometric sequence
for the sum where the initial value is a₁ and the common ratio is r and the term is n

common ratio is -3
-5 times -3 is 15, -15 times -3=-45 etc
first term is -5
and we want the 8th term





the sum is 8200
Let the two numbers be x and y, then
x - y = 48 . . . (1)
x + y = 60 . . . (2)
(1) - (2) => -2y = -12 => y = -12/-2 = 6
From (1), x - 6 = 48 => x = 48 + 6 = 54
Therefore, the two numbers are 54 and 6.
Answer:

Step-by-step explanation:

Distribute the brackets.


Add
on both sides.



Divide
on both sides.


Answer is 9
Step by step explanation
As CB is radius CB=3, CA=3+7=10
X^2=(7+3)^2-3^2=100-9=81
X=9