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3 years ago

Solve the systems of equations 9x+5y=41 and x+y=9 by combining the equations

Mathematics

1 answer:

Sholpan [36]3 years ago

3 0

Step-by-step explanation:

multiplying the 2nd eqn by 9 we get,

9x+9y=81

then,subtracting 1st and 2nd eqn

9x+5y=41

9x+9y=81

- - -

__________

0. -4y=-40

we get y = 10

then we get x=9-y

x=9-10

x= -1

so x is -1 and y is 10

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Find the polynomial.(-1/3,4) is the solution set of

Sholpan [36]

If the solutsion are r1,r2 then the factored form is
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3 years ago

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2x + 3y = 40 5x + 2y = 30

Andrew [12]

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Hi my lil bunny!

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A) Let's solve for x. $2x + 3y = 40$

Step 1: Add -3y to both sides.

$2x + 3y + -3y = 40 + -3y$

$2x = -3y + 40$

Step 2: Divide both sides by 2.

$\frac{2x}{2} = \frac{-3y + 40}{2}$

$x = \frac{-3}{2} y + 20$

Answer : $\frac{-3}{2} y + 20$

~~~~~~~~~~~~~~~~~

B) Let's solve for x. $5x + 2y = 30$

Step 1: Add -2y to both sides.

$5x + 2y + -2y = 30 + -2y$

$5x = -2y + 30$

Step 2: Divide both sides by 5.

$\frac{5x}{5} = \frac{-2y + 30}{5}$

$x = \frac{-2}{5} y + 6$

Answer : $\frac{-2}{5} y + 6$

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Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

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4 years ago

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