Answer:
d. 22
Step-by-step explanation:
(PQ + QR) × QR = (TS + SR) × SR => two secants intersecting theorem
PQ = ?
QR = 2
TS = 8
SR = 4
Plug in the values
(PQ + 2) × 2 = (8 + 4) × 4
2PQ + 4 = 12 × 4
2PQ + 4 = 48
2PQ + 4 - 4 = 48 - 4
2PQ = 44
2PQ/2 = 44/2
PQ = 22
9514 1404 393
Answer:
B, C
Step-by-step explanation:
The sums are ...
A) 59.45
B) 118.16
C) 18.97
D) 27.76
Sums B and C have 8 in the ones place.
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You can add the ones-place digits. If the resulting ones-digit is 7 or 8, then add the tenths-place digits. If the carry from that sum, added to the sum of ones-place digits, gives a value of 8 or 18, then you found a sum with a ones digit of 8.
Sixty-three, 60 + 3, 9 x 7, 63
How to write an equivalent expression for n time a using o
