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Ghella [55]
3 years ago
7

the sum of three numbers is 6. the third number is the sum of the first and second numbers. the first number is one more than th

e third number. Find the numbers
Mathematics
2 answers:
asambeis [7]3 years ago
8 0
<span>x is the first number
y is the second number
z is the third number 
Given
x + y + z = 6 (</span><span>The sum of three numbers is 6)
</span>z = x + y (<span>the third number is the sum of the first and second numbers)
</span><span>x = z + 1  (</span><span>the first number is one more than the third number)
</span><span>
x + y + z=6
z + z  = 6 (because z = x + y)
2 z = 6

Divide both sides by 2 then
z = 3

Replace z = 2 into </span>x = z+1 to find x
x = 3 + 1
x = 4

Replace x = 4 , z = 3 into z = x + y to find y 
3 = 4 + y

Subtract 4 to both sides
3 - 4 = 4 + y -4

Simplify
-1 = y or y = -1

Answer x = 4, y = -1, z = 3 

Proof:
     x + y + z = 6 (The sum of three numbers is 6)
4 + (-1) + 3  = 6
                6  = 6

 z = x + y (the third number is the sum of the first and second numbers)
 3 = 4 + (-1)
 3 = 3

 x = z + 1  (the first number is one more than the third number)
 4 = 3 + 1
4  = 4
Monica [59]3 years ago
6 0
Your numbers would be 1, 2, and 3.

1+2=3 

1+2+3=6
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