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3 years ago

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the length of a rectangle is 8 less than twice the width. the perimeter is 38 feet. Find the length and width. someone please he

lp.

1 answer:

Aleksandr-060686 [28]3 years ago

7 0

Answer:L=4 W=15

Step-by-step explanation:

P=2L+2W

38-8=30

If length is 8 less than twice the width and the perimeter is 38, then subtract 38-8 which is 30, then divide 30 by 2 to get 15.

P=2(4) +2(15)

P=38

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Step-by-step explanation:

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