Question

the length of a rectangle is 8 less than twice the width. the perimeter is 38 feet. Find the length and width. someone please help.

Answer 1

Answer:L=4 W=15

Step-by-step explanation:

P=2L+2W

38-8=30

If length is 8 less than twice the width and the perimeter is 38, then subtract 38-8 which is 30, then divide 30 by 2 to get 15.

P=2(4) +2(15)

P=38