Y=MX+C C=1 0=m(1)+1 m=-1 Y=-X+1
Answer:
81.85%
Step-by-step explanation:
Given :
The average summer temperature in Anchorage is 69°F.
The daily temperature is normally distributed with a standard deviation of 7°F .
To Find:What percentage of the time would the temperature be between 55°F and 76°F?
Solution:
Mean = 
Standard deviation = 
Formula : 
Now At x = 55


At x = 76


Now to find P(55<z<76)
P(2<z<-1)=P(z<2)-P(z>-1)
Using z table :
P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185
Now percentage of the time would the temperature be between 55°F and 76°F = 
Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.
7 stamps. He will give 6 stamps to them each and there will be 7 left
Answer:
?
Step-by-step explanation:
Answer:
11.95 - 7.95 = 4
4/7.95 = 0.50314465
0.50314465 X 100= 50.314465
50% rounded to 1dp