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Firdavs [7]
3 years ago
15

Round to the nearest thousandth: 6.49993

Mathematics
1 answer:
Leona [35]3 years ago
6 0

rounding to the thousandth means to the 3rd place after the decimal...

so if you rounded 6.49993 to the nearest thousandth it would be 6.500

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35 2/9 divided 5 8/9
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Answer:

53/405

Step-by-step explanation:

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Find the value of 3 to the power of -3 times 10 to the power of -3
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Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.
loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>
  • x^ax^b = x^{(a+b)}
  • \dfrac{x^a}{x^b} = x^{(a-b)}
  • (a^a)^b =x^{(a\times b)}
  • (xy)^a = x^ay^a
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The solution of the expression is \dfrac{4x^4}{y^6}.

<h2>Explanation</h2>

Given to us

  • (16x^8y^{12})^{\frac{1}{2}}

Solution

We know that 16 can be reduced to 2^4,

=(2^4x^8y^{12})^{\frac{1}{2}}

Using identity (xy)^a = x^ay^a,

=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}

Using identity (a^a)^b =x^{(a\times b)},

=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})

Solving further

=2^2x^4y^{-6}

Using identity \dfrac{x^a}{x^b} = x^{(a-b)},

=\dfrac{2^2x^4}{y^6}

=\dfrac{4x^4}{y^6}

Hence, the solution of the expression is \dfrac{4x^4}{y^6}.

Learn more about Exponentiation:

brainly.com/question/2193820

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2 years ago
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Credit to the person below-

3 0
3 years ago
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what types of problems can be solved using the greatest common factor what types of problems can be solved using the last common
jonny [76]

Answer:

The greatest common factor is the biggest factor that divides two different numbers. For example, the greatest common factor of 6 and 8 is 2. The least common multiple is the smallest number that two numbers share as a multiple. For example, 12 is a the lowest common multiple of 3 and 4.

Step-by-step explanation:

3 0
4 years ago
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