the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
Step-by-step explanation:
hello : note 297 no 279
297 =3×99
99 = 3 ×33
33=3×11
this the geometric sequence. ( comon : 3)
the nth term is : An = A1 × r^n when : r = 3 and A1 =11
if n = 19 A19 = 11×3^19
17
linear has 1 as highest exponent
D has x^2
D is not linear
18. find slope
(y2-y1)/(x2-x1)=(-1-2)/(0-4)=-3/-4=3/4
y=3/4x+b
B is answer
c/2-3+6/d
substitute c=14 and d=13:
14/2-3+6/13
simplify:
7-3+6/13
4+6/13
multiply 4 by 13/13 to group like terms (for a fraction):
52/13+6/13
combine:
58/13
Therefore, the answer is 58/13 or around 4.462
<span>one way to solve this kind of problems is by doing a little bit of reversal
75 % * X = 54
75/100 * X = 54
(we move 75/100 to the right, since it's a fraction the top and bottom number will be reversed)
X = 54 * 100/75
X = 5400 / 75
X = 72 Hope I helped! :) Cheers!</span>
