Need help ASAP I need the right answers

A random sample of 625 10-ounce cans of fruit nectar is drawn from among all cans produced in a run. Prior experience has shown

diamong [38]

Answer:

10.57% probability that the mean contents of the 625 sample cans is less than 9.995 ounces.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 10, \sigma = 0.1, n = 625, s = \frac{0.1}{\sqrt{625}} = 0.004$

What is the probability that the mean contents of the 625 sample cans is less than 9.995 ounces?

This is the pvalue of Z when X = 9.995. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{9.995 - 10}{0.004}$

$Z = -1.25$

$Z = -1.25$ has a pvalue of 0.1057

So there is a 10.57% probability that the mean contents of the 625 sample cans is less than 9.995 ounces.

5 0

2 years ago

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac

Fed [463]

Answer:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

Step-by-step explanation:

Factor constant terms:

$-2(-4sin(2\theta)+sin(\theta))=0$

Divide both sides by -2:

$sin(\theta)-4sin(2 \theta)=0$

Expand trigonometric functions using the fact:

$sin(2 \theta) =2 sin(\theta) cos(\theta)$

So:

$sin(\theta) -8sin(\theta)cos(\theta)=0$

Factor sin(x) and constant terms and multiply both sides by -1:

$sin(\theta) (8cos(\theta)-1)=0$

Split into two equations:

$(1)=8cos(\theta)-1=0\\\\(2)=sin(\theta)=0$

For (1)

Add 1 to both sides and divide both sides by 8:

$cos(\theta)=\frac{1}{8}$

Take the inverse cosine of both sides:

$\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z$

For (2)

Simply take the inverse sine of both sides

$\theta = k \pi, \hspace{3}k\in Z$

Therefore, the solutions are given by:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\ \theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

8 0

2 years ago

Making Sense of Slope - Item 32544

Alexeev081 [22]

Answer:

the train track is straight

Step-by-step explanation:

i had that too

8 0

3 years ago

Please answer this correctly without making mistakes

IrinaVladis [17]

Answer:

44 5/6 "the second one"

5 0

3 years ago

Please help :( <br> Properties of Parallelograms

olga2289 [7]

Answer:

sinceramente no entiendo tu idioma.... sprry me encantaria poder ayudarte pero bvueno espero que consigas una respuesta rapida y efectiva no como la mia que fue tan inutil bye

Step-by-step explanation:

7 0

3 years ago