Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
2. B
3.B
4.C
6A. 6
6B. 12
6C. 19.6
6D. 18.75
6E. I cant see
6F. I cant see
Step-by-step explanation:
2. 1/4*40=10
3. type the choice into the calculator
4. 2/5 of 30 or 2/5*30=12
6. A-F type into the calculator
Answer:
5/2cups
Step-by-step explanation:
If a recipe serves 6 and calls for 3/4cups, arecipe that serves 20, will call for (20×3/4)/6 cups. Mathematically;
6recipe = 3/4cups
20recipe = x
Cross multiplying we have;
6x = 20×3/4
6x = 15
x = 15/6
x = 5/2
This means a recipe that serves 20 will call for 5/2cups
Yes your answer would be correct! :)
