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ehidna [41]
3 years ago
13

HELP NEEDED IMMEDIATE PLEASE AND THANKS :)

Mathematics
2 answers:
mylen [45]3 years ago
5 0

Answer:

OMGGGG wanna work on this together I need this question too

joja [24]3 years ago
3 0
Where is the picture?
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Find the equation of a line parallel to line y=6 that passes through the point (-2,-1)
ohaa [14]

Answer:

y=-1

Step-by-step explanation:

yeah-ya...... right?

4 0
2 years ago
PLEASE HELP!! 25 POINTS AWARDED
kondaur [170]

Answer:

The following numbers ARE functions:

2, 3, 6, 7, 9, 12

Step-by-step explanation:

A function is only possible if the x values have NO REPEATING NUMBER!!!

Every number that isn't mentioned above has at least 1 number in it's x-values that repeats.

<u>Question 1</u> has the 8 and 4 with 2 numbers.

<u>Question 4</u> the 3 repeating. (There are 2 dots over the 3)

<u>Question 5</u> has numbers 1 and 5 repeating many times

<u>Question 8</u> numbers 1 and 2 are repeated twice

<u>Question 10</u> number 3 repeats twice

<u>Question 11</u> has the 1 repeated

8 0
3 years ago
Which expression could be used to determine the area of the square? A square has side lengths of 10.75 meters. (2)(10.75) (4)(10
kolezko [41]

Answer:

Step-by-step explanation:

area of square=10.75² m²

or A=(10.75)(10.75)  m²

3 0
3 years ago
Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg lesss strawberries in the morning tha in the afte
Tpy6a [65]

Answer:

3\frac{13}{20}=3.65 kg.

Step-by-step explanation:        

Let S be amount of strawberries picked in the afternoon.

We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are 2\frac{1}{4} kg.

To find the amount of strawberries picked by Sheldon in the afternoon we will add 2\frac{1}{4} and 1\frac{2}{5}  :

S= 2\frac{1}{4}+1\frac{2}{5}      

Upon converting our given mixed fractions into improper fraction we will get,

S= \frac{9}{4}+\frac{7}{5}

Now let us have a common denominator.

S=\frac{9*5}{4*5}+\frac{7*4}{5*4}

S=\frac{45}{20}+\frac{28}{20}

S=\frac{45+28}{20}

S=\frac{73}{20}  

S=3\frac{13}{20}  

S=3.65

Therefore, Sheldon picked 3\frac{13}{20}=3.65 kg of strawberries in the afternoon.  

3 0
3 years ago
Clare estimates that her brother is 4 feet tall. When they get measured at the doctor’s office, her brother’s actual height is 4
chubhunter [2.5K]

Problem 1

The error is 2 inches since her estimate is 2 inches off the true value.

We can think of it like this

4 feet = 4*12 = 48 inches

4 feet, 2 inches = 4 ft + 2 in = 48 in + 2 in = 50 inches

So she guesses he is 48 inches, but he's really 50 inches, so 50-48 = 2 inches is her error.

==================================================

Problem 2

Divide the error (2 inches) over the actual height (50 inches) to get

2/50 = 4/100 = 4%

The percentage error is 4%

This means she is 4% off the target.

Note how 4% of 50 = 0.04*50 = 2 which was the error we found back in problem 1.

8 0
3 years ago
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