Tom bought 2 dozen eggs he found 1/6 of them were bad.how many eggs were bad

Estimate first to the nearest whole number 6.07x3.29

Oksanka [162]

Answer:

6x3=18

Step-by-step explanation:

6 0

3 years ago

four pieces of pie were eaten from a pie cut into equal parts. The 5 pieces that remained created an angle that measured 200°. W

Morgarella [4.7K]

Step-by-step explanation:

The 5 pieces that remained created an angle that measured 200 degree means that the 4 pieces made 360-200 degrees 160o.

If all four made 160 then each has to be 160/4 = 40o

200/5 also gives you 40 (the five remaining)

360/9 would also give you 40 9the 5 remaining and the 4 eaten)

I hope this helps

6 0

3 years ago

A human society has 73 dogs and cats to be adopted. the number of cats is 10 more than twice the number of dogs. Write a system

viktelen [127]

Total: 73
dogs: x
cats: 2x+10

2x+10+x=73
3x+10=73
3x=63
x=21

dogs: x
dogs: 21

cats: 2x+10
cats: 52

Check answer:
cats+dogs=73
52+21=73

There's no need for a system of linear equations if you were to solve a real life problem like this. In calculus, they don't give a rat about HOW you get your answer to an easy algebra 1 equation, as long as you used one of the correct methods and got the right answer.

Best of luck my friend. :)

8 0

3 years ago

A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,

katovenus [111]

Answer:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation

$X_{1}=45$ represent the number of correct answers for university degree holders

$X_{2}=57$ represent the number of correct answers for university non-degree holders

$n_{1}=373$ sample 1 selected

$n_{2}=639$ sample 2 selected

$p_{1}=\frac{45}{373}=0.121$ represent the proportion of correct answers for university degree holders

$p_{2}=\frac{57}{639}=0.0892$ represent the proportion of correct answers for university non-degree holders

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0

3 years ago

Could someone please explain to me how to do this!

Svetlanka [38]

Ohhhh, I did this stuff last year. i wish i can remember... but your best bet is A because that angle is super small so A would be best. Hope I helped brainliest plz

6 0

4 years ago