Question

2

Answer 1

Answer:

The volume of can A is half the volume of can B.

Step-by-step explanation:

Given

Can A and Can B

Required

The true statement

For Can A, we have:

$h =8$

$r = 0.5$

The volume is:

$Volume = \pi r^2h$

This gives:

$V_A = \pi * 0.5^2 * 8$

$V_A = \pi * 2$

$V_A = 2\pi$

For Can B, we have:

$h =4$

$r = 1$

The volume is:

$Volume = \pi r^2h$

This gives:

$V_B = \pi * 1^2 * 4$

$V_B = \pi * 4$

$V_B = 4\pi$

So, we have:

$V_A = 2\pi$

$V_B = 4\pi$

By comparison, (d) is correct