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Misha Larkins [42]
4 years ago
7

A triangle has two sides that measure

Mathematics
1 answer:
mr_godi [17]4 years ago
3 0

Answer:

D,12cm

Step-by-step explanation:

100 percent/TRUST

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Explain the meaning of the table and write the constant of proportionality in an equation. Susan is going to the library from ho
aleksley [76]

Answer:

it depends on how long it takes her to get there

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Explain how you can find a fraction that is theequivalent to 1/4
Lana71 [14]
Well you could simplify the fraction(s) in question to their smallest form (where you can’t divide anymore without getting decimal answers) and see if they are equal to 1/4.

For example 2/8, you can divide both sides by 2 to simplify to 1/4, thus 2/8 is equivalent to 1/4.

Hope this helps!
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A certain group of women has a 0.94% rate of red/green color blindness. If a woman is randomly selected, what is the probability
DiKsa [7]

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99.06%

Step-by-step explanation:

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8 0
3 years ago
What is the sum of series is numbers 64&amp;66 ?<br> Using the summation notation
iragen [17]

Answer:

64. 6138

66. 8.078125

Step-by-step explanation:

Let's take it one number at a time.

For number 64:

6(2)^{1-1}=6

6(2)^{2-1}=12

6(2)^{3-1}=24

6(2)^{4-1}=48

6(2)^{5-1}=96

6(2)^{6-1}=192

6(2)^{7-1}=384

6(2)^{8-1}=768

6(2)^{9-1}=1536

6(2)^{10-1}=3072

Sum = 6 + 12 + 24 + 48 + 96 + 192 + 384 + 768 + 1536 + 3072

Sum = 6138

For number 66:

12(-\frac{1}{2})^{0}=12

12(-\frac{1}{2})^{1}=-6

12(-\frac{1}{2})^{2}=3

12(-\frac{1}{2})^{3}=-1.5

12(-\frac{1}{2})^{4}=0.75

12(-\frac{1}{2})^{5}=-0.375

12(-\frac{1}{2})^{6}=0.1875

12(-\frac{1}{2})^{7}=-0.0078125

12(-\frac{1}{2})^{8}=0.046875

12(-\frac{1}{2})^{9}=-0.0234375

Sum = 12 + -6 + 3 + -1.5 + 0.75 + -0.375 + 0.1875 + -0.0078125 + 0.046875 + -0.0234375

or to make things simpler:

Sum = 12 - 6 + 3 - 1.5 + 0.75 - 0.375 + 0.1875 - 0.0078125 + 0.046875 - 0.0234375

Sum = 8.078125

4 0
3 years ago
⚠⚠I SEE YOU DONT YOU DARE IGNORE THIS⚠⚠⚠⚠
hammer [34]

Answer:

2=(3,-2)

3=(-4.75,-6.25)

4=(5/2,3/2)

5=87.8(simplified)

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3 years ago
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