3 years ago

Can anyone please help me out and god bless yall!!!

Mathematics

2 answers:

Brrunno [24]3 years ago

8 0

Answer:

B'(4;5) L'(5,0) S'(2,2l

Arada [10]3 years ago

4 0

Answer:

The answer is the number two answer.

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3 years ago

I NEED HELP PLEASE. LOOK AT PICTURE

Bond [772]

Answer:

Part 1) $\frac{a^4}{4b^2}$

Part 2) $-\frac{v^9}{w^6}$

Step-by-step explanation:

we know that

When divide exponents (or powers) with the same base, subtract the exponents

Part 1) we have

$\frac{3a^{2}b^{-4}}{12a^{-2}b^{-2}}=(\frac{3}{12})(a^{2+2})(b^{-4+2} )=\frac{1}{4}a^{4}b^{-2}=\frac{a^4}{4b^2}$

Part 2) we have

$\frac{v^3w^{-3}}{-v^{-6} w^3} =-v^{3+6}w^{-3-3}=-v^9w^{-6}=-\frac{v^9}{w^6}$

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3 years ago

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kakasveta [241]

A is 0.

B is 7.

C. is 3.

D is 0.

I dont know E.

F is 3.

G is 0.

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3 years ago