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sertanlavr [38]
3 years ago
13

Write an equation of the line with the given slope and y-intercept.

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0
Y=-1/3X-1 should be correct
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Solve 8(3x-4)=4x-2. Help
FinnZ [79.3K]
X = 3/2

<em><u>I hope this could help!</u></em>
8 0
3 years ago
Read 2 more answers
A shipping container contains seven complex electronic systems. Unknown to the purchaser, two are defective. Two of the seven ar
kodGreya [7K]

Answer:

     \large\boxed{\large\boxed{10/21}}

Explanation:

There are only two mutually exclusive possibilities for each complex electronic system: being <em>defective</em> or being <em>not defective</em>:

  • Number of complex electronic systems: 7
  • Nmber of defective systems: 2
  • Number of not defective systems: 5

<em>Probability </em>that no defective systems are found in the sample is the equal to the probability of selecting them consecutively without replacement and finding each one is not defective:

  • Porbability the first is not defective × probability the second is not defective

  • 5/7 × 4/6 = 20/42 = 10/21

4 0
3 years ago
A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0
3 years ago
HELPPPPPPPP!!!!!!!!!!
Novosadov [1.4K]

Step-by-step explanation:

98 = 188t - 16t^2

-16t^2 + 188t = 98

-16t^2 + 188t - 98 = 0

8t^2 - 94t + 49 = 0

Use the quadratic formula with a = 8 , b = -94 , c = 49 to get the solutions

t = [(47 - root 1817) / 8]≈ 0.55

and

t = [(47 + root 1817) / 8] ≈ 11.20

8 0
3 years ago
Plz help me with this ASAP
VLD [36.1K]

Answer:

Step-by-step explanation:

plug all in

1) 0 when x=0

2) 1*6-1²=6-1=5

3) 6*2-2²=12-4=8

4)6*3-3²=18-9=9

5) 6*4-4²=24-16=8

6)6*5-5²=30-25=5

7) 6*6-6²=36-36=0

6 0
3 years ago
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