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3 years ago

I need help with my work

Mathematics

1 answer:

erica [24]3 years ago

4 0

Answer:

number 6 is -8 number 7 is 9 number 8 is 25 and number 9 is -16

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Sushil is 6 years older than Brian. Caroline is 5 years younger than Brian. If the total of their ages is 64, how old is the you

Nadusha1986 [10]

Answer:

16 years old

Step-by-step explanation:

Let's use the letters s, b, and c for Sushil, Brian, and Caroline's ages. Sushil is the oldest, followed by Brian, and then Caroline, the youngest. From the problem description, we can set up three equations:

s = b + 6 <em>(Sushil is 6 years older than Brian)</em>

c = b - 5 <em>(Caroline is 5 years younger than Brian)</em>

s + b + c = 64 <em>(The total of their ages is 64)</em>

Since s and c are already in terms of b, we can substitute them into the last equation and solve to find Brian's age:

(b + 6) + b + (b - 5) = 64

3b + 1 = 64

3b = 63

b = 21

Now that we know Brian's age, we can simply subtract 5 to find Caroline's:

c = b - 5 = 21 - 5 = 16 years old.

8 0

3 years ago

A city has a population of 290,000 people. Suppose the population grows by 3%. What will the population be after 11 years?

LiRa [457]

Assuming it grows 3% each year it would be <span>385,700</span>

4 0

3 years ago

Read 2 more answers

Which pair of angles are an example of supplementary angles?

patriot [66]

Answer:

<h3>A Angle 1 and Angle 7 </h3>

Step-by-step explanation:

<h3> I think the Answer is A...</h3>

If you like this answer then mark this answer as BRAINLIEST answer....

Thank you ☺️☺️

5 0

3 years ago

Read 2 more answers

Simplify each expression. Assume that all variables are positive.

kozerog [31]

Q1. The answer is $\frac{8x^{3}y^{6} }{27}$

$( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} } \\ \\ 
 \frac{ x^{a} }{ x^{b} }= x^{a-b} \\ \\ 
( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}} )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\ \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=$
$\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\ \\ 
 (x^{a} )^{b} = x^{a*b} \\ \\ 
\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } = \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} =$
$= \frac{8x^{3}y^{6} }{27}$

Q2. The answer is 1/16

$(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} = \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\ \\ (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } } \\ \\ 
$
$\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } = \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}$

Q3. The answer is $a^{ \frac{7}{6} }$

$a^{ \frac{2}{3} } * a^{ \frac{1}{2} } \\ \\ 
 x^{a}* x^{b} =x^{a+b} \\ \\ 
a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }$

7 0

3 years ago

What is the inverse of the given relationship?

timofeeve [1]

Answer:

An inverse relation is the set of ordered pairs obtained by interchanging the first and second elements of each pair in the original function. If the graph of a function contains a point (a, b), then the graph of the inverse relation of this function contains the point (b, a).

Step-by-step explanation:

Brainliest when you can if you will.

5 0

3 years ago

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