Answers:
Each yes/no answer refers to the question "is this a function?"
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Explanation:
The last equation is not a function because of the even exponent over the y term. If you apply the fourth root to both sides, you'll end up with y = |x| and y = -|x| as the two possibilities. For any nonzero x, there are multiple y outputs.
The first three equations are functions because we don't have the same issue as the last equation. All exponents for the y terms are odd. Something like y without an exponent really means y^1.
Answer:
ln|sec θ + tan θ| + C
Step-by-step explanation:
The integrals of basic trig functions are:
∫ sin θ dθ = -cos θ + C
∫ cos θ dθ = sin θ + C
∫ csc θ dθ = -ln|csc θ + cot θ| + C
∫ sec θ dθ = ln|sec θ + tan θ| + C
∫ tan θ dθ = -ln|cos θ| + C
∫ cot θ dθ = ln|sin θ| + C
The integral of sec θ can be proven by multiplying and dividing by sec θ + tan θ, then using ∫ du/u = ln|u| + C.
∫ sec θ dθ
∫ sec θ (sec θ + tan θ) / (sec θ + tan θ) dθ
∫ (sec² θ + sec θ tan θ) / (sec θ + tan θ) dθ
ln|sec θ + tan θ| + C
Answer:
Distance, rate and time problems are a standard application of linear equations. When solving these problems, use the relationship rate (speed or velocity) times time equals distance. For example, suppose a person were to travel 30 km/h for 4 h.
Answer:
2
Step-by-step explanation:
This is the picture of the line
good luck