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adell [148]
3 years ago
13

What is this equal how can I solve similar trigonometric integrals like this one

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

ln|sec θ + tan θ| + C

Step-by-step explanation:

The integrals of basic trig functions are:

∫ sin θ dθ = -cos θ + C

∫ cos θ dθ = sin θ + C

∫ csc θ dθ = -ln|csc θ + cot θ| + C

∫ sec θ dθ = ln|sec θ + tan θ| + C

∫ tan θ dθ = -ln|cos θ| + C

∫ cot θ dθ = ln|sin θ| + C

The integral of sec θ can be proven by multiplying and dividing by sec θ + tan θ, then using ∫ du/u = ln|u| + C.

∫ sec θ dθ

∫ sec θ (sec θ + tan θ) / (sec θ + tan θ) dθ

∫ (sec² θ + sec θ tan θ) / (sec θ + tan θ) dθ

ln|sec θ + tan θ| + C

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N + 3m; use m = 3, and n = 1
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Step-by-step explanation:

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4 0
3 years ago
The student then emptied the flask and dired it once again. To the empty flask he added pieces of a metal until the flask was bo
spayn [35]

Answer:

The question is incomplete, below is the complete question:

The volume of a flask has been determined to be 26.918 mL, and the mass of the flask has been determined to be 32.634g. The student then emptied the flask and dried it once again. To the empty flask, he added pieces of metal until the flask was about half full. He weighed the stoppered flask containing the metal and found that its mass was 100.356g. Next, he filled the flask containing the metal with water, stoppered it, reweighed it and obtained a total mass of 121.860g.

a.) Find the mass of the metal in the flask. (show work)

b.) Find the mass of water in the flask. (show work)

c.) Find the volume of water in the flask. (show work)

d.) Find the volume of metal in the flask (show work)

e.) Find the density of the metal. (show work)

Answers:

a.  mass of metal in the flask = 67.722g

b. mass of water in the flask = 21.504g

c. volume of water in the flask = 21.562mL

d.) volume of metal in the flask = 5.356mL

e.) density of the metal = 12.644g/mL

Step-by-step explanation:

a.) mass of metal in the flask = (mass of flask + metal) - mass of empty flask

= 100.356 - 32.634 = 67.722g

b.) mass of water in the flask = (mass of flask when filled with metal and water) - (mass of flask when filled with metal alone)

= 121.860 - 100.356 = 21.504g

c. volume of the water in the flask :

in order to calculate the volume of water in the flask, the density formula is used as follows:

density = mass ÷ volume

volume = mass ÷ density.

where:

Density of water = 0.9973 g/mL

Mass of water as calculated above = 21.504g

∴ volume of water = 21.504 ÷ 0.9973 = 21.562mL

d.) volume of the metal in the flask:

Next, to calculate the volume of the metal in the flask:

volume of flask = volume of metal + volume of water

∴ volume of metal = volume of flask - volume of water

where:

volume of flask = 26.918mL (given)

volume of water = 21.562mL (calculated above)

∴ volume of metal = 26.918 - 21.562 = 5.356mL

e.) density of the metal:

Density = mass ÷ volume

where:

mass of metal = 67.722g ; volume of metal = 5.356mL

∴ Density of metal = 67.722 ÷ 5.356 = 12.644g/mL

4 0
3 years ago
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