Question

One question simple please help

Answer 1

Answer:

$y = \frac{1}{3}x - 9$

Step-by-step explanation:

Standard equation of a line is y = mx + b, where m is the slope.

Given line y = - 3x + 78, slope, m₁ = -3

To find the line perpendicular to the given line.

The lines are perpendicular to each other if the product of their slopes = - 1

That is,

         $m_1 \times m_2 = -1$

So the slope of new line is

                                                   $-3 \times m_2 = -1\\\\m_2 = \frac{-1}{-3} = \frac{1}{3}$

$Therefore , equation \ of \ new \ line \ \\\\(y - y_1) = m_2(x - x_1) , where \ (x_1 , y_1) = (9, -6 )\\\\(y - (-6))= \frac{1}{3}(x -9)\\\\y + 6 = \frac{1}{3} x - 3\\\\y = \frac{1}{3}x -3-6\\\\y = \frac{1}{3}x -9$