Answer:

Step-by-step explanation:
step 1
Find the area of the plate
The area of a circle is given by the formula

we have
---> the radius is half the diameter
substitute

step 2
Find the area of the square napkin folded (is a half of the area of the square napkin)
we know that
The diagonal of the square is the same that the diameter of the plate
Applying Pythagorean theorem

where
b is the length side of the square
we have

substitute

solve for b^2
-----> is the area of the square
Divide by 2

step 3
Find the area of the space on the plate that is NOT covered by the napkin
we know that
The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate
so

simplify

AB is 6 because you just subtract BC from AC to find the other missing length.
Vcylinder=hpir^2
Vsphere=(4/3)pir^3
Vcone=(1/3)hpir^2
Vcylinder=15*pi*5^2=375pi in^3
Vsphere=(4/3)*pi*6^3=288pi in^3
Vcone=(1/3)*15*pi*8^2=320pi in^3
greatest is Vcylinder at 375pi in^3
answer is A (cylinder)
Answer:
$600
Step-by-step explanation:
subtract 45 from 75, you get 30. multiply 30 by 20, and there is your answer.