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Levart [38]
2 years ago
10

A man goes into business for himself selling dog houses. The materials for the dog houses cost him $45 per house. He sells them

for $75 each. How much money does he earn if he sells 20
Mathematics
1 answer:
Aleks [24]2 years ago
7 0

Answer:

$600

Step-by-step explanation:

subtract 45 from 75, you get 30. multiply 30 by 20, and there is your answer.

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The function v(r) 4/3 pie r to the 3rd = can be used to find the volume of air inside a basketball given its radius. What does V
umka21 [38]

Answer:

  the volume of the basketball when the radius is r

Step-by-step explanation:

V(r) is a function name V and argument list (r). Often the letter of the function name is a reminder of what the function computes. Here, V is chosen as the name because it computes Volume. The function uses r (for radius) as its independent variable. That is why r is listed in parentheses next to the function name.

So, V(r) represents a function that computes the volume of a sphere with radius r.

6 0
2 years ago
The population of bacteria in a petri dish doubles every 12 h. The population of the bacteria is initially 500 organisms. How lo
Alenkasestr [34]

Answer:

The answer is 8.1 h




Good luck!!!!!

Step-by-step explanation:


6 0
3 years ago
What is the volume of the sphere in terms of pie
NeTakaya

Answer: The volume is 288π .

Step-by-step explanation:

V= 4/3 *n*r^3

V = 4/3*n * 6^3

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v= 288n

6 0
3 years ago
Help me please due tomorrow!!
Vladimir79 [104]
4 2/3 into improper fracking would be 14/3 now times 3 , 3 and 3 go into 1 so your left with 24 so THATS the answer in other words it would be 42/3 which goes into 14 times:)
6 0
3 years ago
What is the limit of f (×) as x approaches - infinty
tatyana61 [14]
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}

Hope this helps.
5 0
3 years ago
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