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hjlf
3 years ago
15

Match each of the unknown ions to its appropriate description. Match Term Definition V3− A) A nonmetal that gained one electron

X− B) A nonmetal that gained three electrons Y+ C) A metal that lost one electron Z3+ D) A metal that lost three electrons
Chemistry
1 answer:
lozanna [386]3 years ago
4 0
<h3>Answer:</h3>

V3− B) A nonmetal that gained three electrons

X− A) A nonmetal that gained one electron

Y+ C) A metal that lost one electron

Z3+ D) A metal that lost three electrons

<h3>Explanation</h3>
  • Neutral atoms of elements in the periodic table react by gaining or losing electrons to attain a stable configuration according to the octet rule.
  • Atoms of metals react by losing electrons to attain a stable configuration and form positively charged ions known as cations.
  • For example, a neutral sodium atom, Na, would gain one electron to form a cation of sodium, Na⁺.
  • Atoms of non-metals, on the other hand, react by gaining electrons to attain stable configuration and form negatively charged ions known as anions.
  • For instance, a neutral chloride, Cl, atom requires to gain one electron to attain stability and form a chloride anion, Cl⁻.
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In the laboratory you dissolve 23.8 g of manganese(II) nitrate in a volumetric flask and add water to a total volume of 125 . mL
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The correct answer is 1.06 M

Step-by-step explanation:

We have to calculate the molarity (M), which is:

M= moles solute/ 1 L solution.

The chemical formulae of manganese (II) nitrate is Mn(NO₃)₂. So, we first calculate its molecular weight (Mw) as follows:

Mw(Mn(NO₃)₂)= molar mass Mn + (2 x molar mass N) + (6 x molar mass N)= 55 g/mol + (2 x 14 g/mol) + (6 x 16 g/mol) = 179 g/mol

Then, with Mw we calculate the number of moles there is in the given mass of Mn(NO₃)₂:

moles Mn(NO₃)₂= mass/Mw= 23.8 g/(179 g/mol)= <em>0.133 mol</em>

Now, we need the final volume in liters, so we convert the volume from mL to L:

125 mL x 1 L/1000 mL = <em>0.125 L</em>

Finally, we divide the moles of Mn(NO₃)₂ into the volume in L, to obtain the molarity in mol/L:

M= 0.133 moles/0.125 L = 1.06 mol/L= 1.06 M

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