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3 years ago

The photo shows a frozen juice pop on a hot day.

Chemistry

2 answers:

GaryK [48]3 years ago

6 0

Answer:

Arrows pointing from the sun to the juice pop

Explanation: Trust I got it right

Alekssandra [29.7K]3 years ago

3 0

Answer:

C! Hope this helps !:)

Explanation:

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Which apparent motion can be explained by a geocentric model ?

baherus [9]

Answer:

The sun's path through the sky ( i hope this helps)

7 0

3 years ago

The K w for water at 0 ∘ C is 0.12 × 10 − 14 M 2 . Calculate the pH of a neutral aqueous solution at 0 ∘ C . p H = Is a pH = 7.2

Karo-lina-s [1.5K]

Answer:

pH → 7.46

Explanation:

We begin with the autoionization of water. This equilibrium reaction is:

2H₂O ⇄ H₃O⁺ + OH⁻ Kw = 1×10⁻¹⁴ at 25°C

Kw = [H₃O⁺] . [OH⁻]

We do not consider [H₂O] in the expression for the constant.

[H₃O⁺] = [OH⁻] = √1×10⁻¹⁴ → 1×10⁻⁷ M

Kw depends on the temperature

0.12×10⁻¹⁴ = [H₃O⁺] . [OH⁻] → [H₃O⁺] = [OH⁻] at 0°C

√0.12×10⁻¹⁴ = [H₃O⁺] → 3.46×10⁻⁸ M

- log [H₃O⁺] = pH

pH = - log 3.46×10⁻⁸ → 7.46

8 0

3 years ago

The pictures to the right, show two different models

OverLord2011 [107]

Answer:model B

Explanation:

Edge 2020

8 0

3 years ago

Read 2 more answers

A metal X loses 2 electrons and a non-metal Y gains 1 electron. Show the electron dot structure of compound formed between them.

Stells [14]

Answer:

The compound is ionic

The compound has a high melting point

The compound will conduct electricity in aqueous solution

The compound will be soluble in water

Explanation:

Now, let us consider the nature of the compound formed when a metal X looses two electrons and a non metal Y accepts one electron.

The compound formed must be ionic in nature with a formula XY2. Ionic compounds are formed by transfer of electrons from metals to nonmetals.

The ionic substance formed is always soluble in water with a high melting point. Usually, ionic solids do not conduct electricity in the solid state because the charge carriers (ions) are tightly bound in the crystal structure while in the solid state. In aqueous solution, the ions are relatively free hence ionic substances conduct electricity in aqueous solution.

6 0

3 years ago

Calculate the concentration of H3O⁺ in a solution that contains 5.5 × 10-5 M OH⁻ at 25°C. Identify the solution as acidic, basic

harina [27]

Answer : The correct option is, (A) $1.8\times 10^{-10}M$ , basic.

Explanation : Given,

Concentration of $OH^-$ ion = $5.5\times 10^{-5}M$

First we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (5.5\times 10^{-5})$

$pOH=4.26$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-4.26=9.74$

Now we have to calculate the $H_3O^+$ concentration.

$pH=-\log [H_3O^+]$

$9.74=-\log [H_3O^+]$

$[H_3O^+]=1.8\times 10^{-10}M$

As we know that, when the pH value is less than 7 then the solution acidic in nature and when the pH value is more than 7 then the solution basic in nature.

From the pH value, 9.74 we conclude that the solution is basic in nature because the value of pH is greater than 7.

Therefore, the $H_3O^+$ concentration is, $1.8\times 10^{-10}M$ , basic.

3 0

4 years ago