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Blizzard [7]
3 years ago
12

The photo shows a frozen juice pop on a hot day.

Chemistry
2 answers:
GaryK [48]3 years ago
6 0

Answer:

Arrows pointing from the sun to the juice pop

Explanation: Trust I got it right

Alekssandra [29.7K]3 years ago
3 0

Answer:

C! Hope this helps !:)

Explanation:

You might be interested in
A student measures a mass of an 8cm3 block of brown sugar to be 19.9G. what is the density of the brown sugar?
Naily [24]

Answer:

<h2>2.49 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{19.9}{8}  \\  = 2.4875

We have the final answer as

<h3>2.49 g/cm³</h3>

Hope this helps you

3 0
3 years ago
What are the different phases of matter and their characteristics?
Novay_Z [31]

Answer:

The five phases of matter. There are four natural states of matter: Solids, liquids, gases and plasma. The fifth state is the man-made Bose-Einstein condensates. In a solid, particles are packed tightly together so they don't move much.

3 0
3 years ago
Read 2 more answers
A nickle is about 2 millimeters thick, or 2/1000 of a meter.how many nanometers is this?
Softa [21]
You know that you can just google it right? It has this converter.
8 0
4 years ago
What element is being oxidized in the following redox reaction?
GrogVix [38]

Answer:

The O is being oxidized, but at the same time, is being reducted.

Explanation:

H₂O₂(l) + ClO₂(aq) → ClO₂(aq) + O₂(g)

In this reaction, we have 4 compounds:

Hydrogen peroxide

Chlorine dioxide (twice)

Oxygen

In both dioxide, the Cl acts with +4 in oxidation state; the oxygen acts with -2.

Oxgen in ground state has 0, as oxidation number.

In peroxide, the H acts with +1 but  the oxygen acts with -1.

Peroxide is making the oxidation number from the O in the ClO₂, to decrease (reduction) and to increase in the O, at the ground state.

Hydrogen peroxide is a good reducing and oxidizing agent at the same time.

4 0
3 years ago
Calculate the equilibrium constant at 25 ∘C for the reaction Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)
Murrr4er [49]

Answer:

1.7 × 10 ^42

Explanation:

Using Nernst equation

E°cell = RT/nF Inq

at equilibrium

Q=K

E°cell  = 0.0257 /n Ink= 0.0592/n log K

Fe2+(aq)+2e−→Fe(s)     E∘= −0.45 V

Ag+aq)+e−→Ag(s)         E∘= 0.80 V

Fe(s)+2Ag+(aq)→Fe2+(aq)+2Ag(s)

balance the reaction

Fe → Fe²⁺ + 2e⁻  reversing for oxidation E° = 0.45 v

2 Ag⁺ +2e⁻ → 2Ag

n = 2 moles  and K = equilibrium constant

E° cell = 0.80 + 0.45 = 1.25 V

E° cell = (0.0592 / n) log K  

substitute the value into the equations and solve for K

(1.25 × 2) / 0.0592  = log K

42.23 = log K

k = 10^ 42.23

K = 1.7 × 10 ^42

8 0
3 years ago
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