Answer:
22.77 g.
he limiting reactant is O₂, and the excess reactant is Mg.
Explanation:
- From the balanced reaction:
<em>Mg + 1/2O₂ → MgO,</em>
1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.
- We need to calculate the no. of moles of (16.3 g) of Mg and (4.52 g) of oxygen:
no. of moles of Mg = mass/molar mass = (16.3 g)/(24.3 g/mol) = 0.6708 mol.
no. of moles of O₂ = mass/molar mass = (4.52 g)/(16.0 g/mol) = 0.2825 mol.
So. 0.565 mol of Mg reacts completely with (0.2825 mol) of O₂.
<em>∴ The limiting reactant is O₂, and the excess reactant is Mg (0.6708 - 0.565 = 0.1058 mol).</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of Mg produce → 1.0 mol of MgO.
∴ 0.565 mol of Mg produce → <em>0.565 mol of MgO.</em>
<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.565 mol)(40.3 g/mol) = <em>22.77 g.</em>
Kool-Aid itself is actually a mixture of sugar, water, dye, and flavoring. So when we add our sugar crystals, the water molecules and sugar molecules in the Kool-Aid will come in contact with the surface of our pure sugar crystals.
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Answer:
evaporates
Explanation:
the heat from the sun causes it to evaporate
Answer:
Straight-run gasoline. Fractional distillation of crude oil yields a product boiling between 30°C and about 200°C, known as straight-run gasoline (or sometimes as “naphtha”).
Answer:
Percent yield = 65.2 %
Explanation:
The reaction determines this:
2 moles of Al react to 3 moles of chlorine gas in order to produce 2 mol of aluminum chloride.
We determine the moles of chlorine:
52 g . 1mol /70.9g = 0.733 moles of Cl₂
3 moles of gas can produce 2 moles of salt
Then, our 0.733 moles may produce (0.733 . 2) / 3 = 0.489 moles of AlCl₃
We convert moles to mass to predict the 100 % yield
0.489 mol . 133.3 g /mol = 65.19 g
Percent yield = (Yield produced / 100 % yield) . 100
Percent yield = (42.5 g / 65.19g) . 100 = 65.2 %
