55
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99. Hope this helps
The probability for choosing green and red is 
<u>Solution:</u>
Given that , A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble.
We have to find what is the probability of choosing a green marble, not replacing it, and then choosing a red marble?
Now, we know that,
So, total possible outcomes = 1 red + 1 yellow + 1 blue + 1 green = 4
And now, total outcomes will be only 3 as we are not replacing the picked marble.
Hence, the probability for choosing green and red is
(a) 
since 13 is prime.
(b) 
, and there are 81/3 = 27 multiples of 3 between 1 and 81, which leaves 81 - 27 = 54 numbers between 1 and 81 that are coprime to 81, so 
.
(c) 
; there are 50 multiples of 2, and 20 multiples of 5, between 1 and 100; 10 of these are counted twice (the multiples of 2*5=10), so a total of 50 + 20 - 10 = 60 distinct numbers not coprime to 100, leaving us with 
.
(d) 
; there are 51 multiples of 2, 34 multiples of 3, and 6 multiples of 17, between 1 and 102. Among these, we double-count 17 multiples of 2*3=6, 3 multiples of 2*17=34, and 2 multiples of 3*17=51; we also triple-count 1 number, 2*3*17=102. There are then 51 + 34 + 6 - (17 + 3 + 2) + 1 = 70 numbers between 1 and 102 that are not coprime to 102, and so 
.
The answer is $6.85
Every day she puts in .33 cents.
So 6 days is $1.98
1.98+4.87=6.85
hope this helps
Do you mean checking your work? In that case it would be 9*20.
