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4 years ago

Was I right for 46 but 47 I need help with

Mathematics

1 answer:

Julli [10]4 years ago

7 0

You are not right on #46. Since he is going 50 miles in 50 minutes, that means that he is going a mile a minute. That means in an hour, he will have gone 60 miles. That means he will have been going 60 mph, so the correct answer is (4)

I cannot help you with 47 because you did not include the picture it shows.

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Ava bought a collection of hardcover novels and paid $450 including sales tax the sales tax 10% How much was the price of collec

scoray [572]

Answer:

The price of collection of novels before taxes was $409.10.

Step-by-step explanation:

Given:

Ava bought a collection of hardcover novels and paid $450 including sales tax.

The sales tax is 10%.

Now, to find the price of collection of novels before taxes.

Let the price of collection of novels before sales tax be $x$ .

The price of collection of novels including sales tax = $450.

Rate of sales tax = 10%.

Now, to get the price before sales tax by putting an equation:

$x=450-10\%\ of\ x$

$x=450-\frac{10}{100} \times x$

$x=450-0.10\times x$

$x=450-0.10x$

Adding both sides by 0.10 $x$ we get:

$1.10x=450$

Dividing both sides by 1.10 we get:

$x=\$409.10.$

Therefore, the price of collection of novels before taxes was $409.10.

5 0

3 years ago

HELP ASAP WILL MARK BRAINLIEST AREA OF FIGURES

Lerok [7]

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$(3.14)(2.5)^{2}(7)$ *Square 2.5*

$(3.14)(6.25)(7)$ *Solve*

≈ $137.375in^{3}$

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(2.5)^{3}$ *Cube 2.5*

$\frac{\frac{4}{3}(3.14)(15.625)}{2}$ *Divide by 2 and Solve*

≈ $32.7083 in^{3}$

Add both volumes

$137.375 + 32.7083$ ≈ $170.083in^{3}$

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (3)^{2}(10)$ *Square 3*

$\pi (9)(10)$ *Multiply*

$90\pi$

Sphere:

$V = \frac{4}{3}$ π $r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (3)^{3}$ *Cube 3*

$\frac{4}{3} \pi (27)$ *Multiply*

$36\pi$

Add both Volumes to get total

$90\pi + 36\pi = 126in^{3}$

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(3)^{3}$ *Cube 3*

$\frac{4}{3} (3.14)(27)$ *Multiply*

$113.04m^{3}$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{(3.14)(2)^{2}(5)}{3}$ *Square 2*

$\frac{(3.14)(4)(5)}{3}$ *Solve*

$20.93m^{3}$

Subtract the volumes to get the volume of the blue area

$113.04 - 20.93 = 92.106m^{3}$

Sphere:

$V = \frac{4}{3} \pi r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (8)^{3}$ *Cube 8*

$\\\frac{4}{3}\pi (512)$ *Multiply*

$\\\\\pi (682.6)$ *Solve*

$2133.66in^{3}$ *Divide by 2 since it's a hemisphere*

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (8)^{2}(20)}{3}$ *Square 8*

$\frac{\pi (64)(20)}{3}$ *Multiply and Divide*

$1340.41 in^{3}$

Add both volumes

$1072.33 + 1340.41 = 2412.74in^{3}$

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (6)^{2}(16)$ *Square 6*

$\pi (36)(16)$ *Multiply*

$576\pi$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (6)^{2}3}{3}$ *Square 6*

$36\pi$

Add both volumes

$576\pi + 36\pi = 612\pi m^{3}$

Alternative: *Multiply π*

$1922m^{3}$

4 0

3 years ago

Read 2 more answers

NEED HELP ASAP!!!

Sergeeva-Olga [200]

Answer:

(b) $P(\textrm{Event of getting a 3 in the spinner)} = \frac{11}{61}$

Step-by-step explanation:

Let E: Event of getting a 3 in the spinner.

So, the number of favorable outcomes = 11

Total number of outcomes = Number of times the outcomes is {1,2,3,4,5,6}

= {13 +10 +11+16+11} = { 61}

So, the total number of outcomes = 61

$\textrm{Probability of Event E} = \frac{\textrm{Number of favorable events}}{\textrm{Total number of outcomes}}$

So, here $P(\textrm{Event of getting a 3 in the spinner)} = \frac{11}{61}$

3 0

3 years ago

Find the area enclosed between f(x)=0.3x2+7 and g(x)=x from x=−4 to x=8.

denis23 [38]

First, we sketch a picture to get a sense of the problem. g(x)=x is a diagonal line through (0,0) with slope = = 1. Since we are interested in the area between x = -4 and x = 8, we find the points on the line at these values. These are (-4, -4) and (8,8).

f(x) is a parabola. It's lowest point occurs when x = 0. It is the point (0,7). At x = -4 and x=8 it has the values 11.8 and 26.2 respectively. That is, it contains the points (-4, 11.8) and (8,26.2).

From these we make a rough sketch (see attachment). This is a sketch and mine is very incorrect when it comes to scale but what matters here is which of the curves is on top, which is below and whether they intersect anywhere in the interval, so my rough sketch is good enough. From the sketch we see that f(x) is always above (greater than) g(x).

To find the area between the curves over the given interval we integrate their difference and since f(x) is strictly greater than g(x) we subtract as follows: f(x) - g(x). The limits of integration are the values -4 and 8 (the x-values between which we are looking for the area.

Now let's integrate:
$\int\limits^{8}_ {-4}f(x)-g(x) \, dx = \int\limits^{8}_ {-4}.3 x^{2} +7-x \, dx$
The integral yields: $[tex](\frac{.3 (8)^{3} }{3} +7(8)- \frac{ (8)^{2} }{2}) -(\frac{.3 (-4)^{3} }{3} +7(-4)- \frac{ (-4)^{2} }{2}) = 117.6$ [/tex]
We evaluate this for 8 and for -4 subtracting the second FROM the first to get:

4 0

3 years ago

Simplify 18-2[x + (x - 5)]. O8-4x 28 - 4x 28 - 2x

densk [106]

Answer:

28-4x

Step-by-step explanation:

Step 1: Open most inner bracket and simplify

=18-2(x+x-5)

=18-2(2x-5)

Step 2: Expand brackets by multiplying 2 in and simplify

=18-2(2x)-2(-5)

=18-4x+10

=28-4x

Therefore the answer is 28-4x

3 0

3 years ago