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Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB =AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.
She worked 2 and 1/2 hours yesterday, and today she did 4 and 1/4 hours.
first off, let's check how many hours she worked total, and divide 54 by it.
so, first off, let's convert the mixed fractions to "improper" and add them up.
first off, let's check how many hours she worked total, and divide 54 by it.
so, first off, let's convert the mixed fractions to "improper" and add them up.