Step-by-step explanation:
You can write an equation of a line conveniently by point-slope form. It's in the form of
where
is the coordinates of a point that's on the line and
is the slope of the line.
Now choose a point (It doesn't really matter which one) and plug that in the equation. I'll choose
where
and 

The next thing we have to do now is finding the slope,
, where it's equal to
. I'll make
point 1 and
point 2.

Now let's plug that to our equation.

Now we have the equation but out of all the choices it seemed that all of them are in slope-intercept form all you have to do now is make our equation rewrite it in slope-intercept form.

<h3>Answer:</h3>
is your equation.
Answer:the mean is 6.1 the mode is 5 and 7.
Step-by-step explanation: the mean is 6.1 because the number add up to 61 and there are 10 numbers 61/10=6.1
The mode is 5 and 7 because they occur most frequently
The value of f(r - 2) is 6r - 5
<h3>What is a function?</h3>
Function can be defined as an expression, rule, or law that defines a relationship between one variable known as the independent variable and another called the dependent variable.
From the information given ,we have;
f(x)= 6x+7, with f ( r - 2)
From here, we have that x = r -2
Now, let's substitute x as r - 2 in the function given;
f(x) = 6x + 7
f(r - 2) = 6 ( r - 2) + 7
Expand the bracket
f(r - 2) = 6r - 12 + 7
collect like terms
f(r - 2) = 6r - 5
Thus, the value of f(r - 2) is 6r - 5
Learn more about functions here:
brainly.com/question/6561461
#SPJ1
Option b. 0.496
- Step-by-step explanation:
we know that
f(x)=0.01(2^{x})
The average rate of change is equal to
\frac{f(b)-f(a)}{b-a}
where
a=3
b=8
f(a)=f(3)=0.01(2^{3})=0.08
f(b)=f(8)=0.01(2^{8})=2.56
Substitute
\frac{2.56-0.08}{8-3}
\frac{2.48}{5}
0.496
Answer:
x = 4
Step-by-step explanation:
It is stated that f(x) passes through
(-3, 3), (0, 3), (4, 3)
and g(x) passes through
(-4, -3), (0, 0), (4, 3)
Therefore, both functions pass through (4, 3). That is, the input value x = 4 produces the same output value y = 3 for the two functions.