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stepladder [879]
3 years ago
5

A ball is thrown into the air with an upward velocity of 28 ft/s. Its height (h) in feet after t seconds is given by the functio

n h=-16t^2+28t+7. How long does it take the ball to reach its maximum height? What is the ball/s maximum height? Round to the nearest hundredth, if necessary.
A. 1.75 s; 7 ft
B. 0.88 s; 43.75 ft
C. 0.88 s; 17.5 ft
D. 0.88 s; 19.25 ft
Mathematics
1 answer:
Yanka [14]3 years ago
3 0
The Answer is D: 

h = -16t^2 + 28t + 7
h' = -32t + 28

-32t + 28 = 0

-32t = -28 

t = .875 seconds

h(.875) = -16(.875^2) + 28(.875) + 7

h(.875) = 19.25 ft
Rounding time to nearest hundredth gives max at (.88s, 19.25ft)
 
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A triangular prism has a length of 5 inches, a base of 2 inches, a height of 2 inches, and sides of 2 inches and 3 inches. Find
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Volume of the Triangular prism = 1/2 (base*height*length) 
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<span>For the surface area, you can divide the prism into parts: </span>
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<span>For the two triangles: </span>
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<span>For the three rectangles: </span>
<span>* one is equal to base x length, </span>
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<span>* another is equal to side 1 x length </span>
<span>Rectangle2 = 3 x 5 </span>
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<span>* and the last is equal to side 2 x length. </span>
<span>Rectangle3 = 3 x 5 </span>
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<span>Adding all the components up, </span>
<span>10 + 15 + 15 + 5 + 5 = 50 inches^2 </span>

<span>Therefore, the surface area of the prism is greater than volume 50 > 10
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