Answer:
6 if pedro and his two brother will have coins. If he doesnt get any for himself and gives it all to his brothers then they each get 9.
Step-by-step explanation:
I used my calculator.
Answer:
Here we will simplify 2/50 to its simplest form and convert it to a mixed number if necessary.
In the fraction 2/50, 2 is the numerator and 50 is the denominator.
When you ask "What is 2/50 simplified?", we assume you want to know how to simplify the numerator and denominator to their smallest values, while still keeping the same value of the fraction.
We do this by first finding the greatest common factor of 2 and 50, which is 2.
Then, we divide both 2 and 50 by the greatest common factor to get the following simplified fraction:
1/25
Therefore, this equation is true:
2/50 = 1/25
If the numerator is greater than or equal to the denominator of a fraction, then it is called an improper fraction. In that case, you could convert it into a whole number or mixed number fraction.
1/25 = Proper Fraction
Step-by-step explanation:
please mark brainliest
Answer:
Pretty sure its 6
Step-by-step explanation:
The hypotenuse is double the length of the shortest side
Answer:
The answer is z = 34.
Step-by-step explanation:
1) Simplify 2 + 8 - z to 10 - z.

2) Subtract 10 from both sides.

3) Simplify - 24 - 10 to -34.

4) Multiply both sides by -1.

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>z</u><u> </u><u>=</u><u> </u><u>34</u><u>.</u>

is a complex number that satisfies
![\begin{cases}r\cos x=-3\\[1ex]r\sin x=4\\[1ex]r=\sqrt{(-3)^2+4^2}\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Dr%5Ccos%20x%3D-3%5C%5C%5B1ex%5Dr%5Csin%20x%3D4%5C%5C%5B1ex%5Dr%3D%5Csqrt%7B%28-3%29%5E2%2B4%5E2%7D%5Cend%7Bcases%7D)
The last equation immediately tells you that

.
So you have
![\begin{cases}\cos x=-\dfrac35\\[1ex]\sin x=\dfrac45\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%5Ccos%20x%3D-%5Cdfrac35%5C%5C%5B1ex%5D%5Csin%20x%3D%5Cdfrac45%5Cend%7Bcases%7D)
Dividing the second equation by the first, you end up with

Because the argument's cosine is negative and its sine is positive, you know that

. This is important to know because it's only the case that

whenever

. The inverse doesn't exist otherwise.
However, you can restrict the domain of the tangent function so that an inverse can be defined. By shifting the argument of tangent by

, we have

All this to say

So,

.