4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2
Anna007 [38]
Answer:
<u>Given data:</u>
- 4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2
<u>Put the data in the ascending order:</u>
- 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6, 8
<u>Mean, the average:</u>
- (1 + 2*5 + 3*4 + 4*4 + 5*2 + 6 + 8)/18 = 3.5
<u>Median, average of middle two numbers:</u>
<u>Mode, the most repeated number:</u>
Mean is normally the best measure of central tendency, same applies to this data.
Answer:
13/12 or 1 1/12
Step-by-step explanation:
First you would convert the 1/6 to 2/12 then add them like normal to get 13/12.
Hope this helps :
Answer:
b(-10) = 6
Step-by-step explanation:
Step 1: Define
b(x) = |x + 4|
b(-10) is x = -10
Step 2: Substitute and Evaluate
b(-10) = |-10 + 4|
b(-10) = |-6|
b(-10) = 6
It’s 2.98 explanation:you divide $65.56 and 22.
C) 1059 skittles
Step-by-step explanation:
We know that the first container held 192 skittles. Knowing the dimension of the container we can calculate the volume of 192 skittles:
Volume of 192 skittles = 5 × 4 × 4 = 80 cm³
Volume of 1 skittle = 80 / 192 = 0.42 cm³
We also know that the second container held 258 skittles. Knowing the dimension of the container we can calculate the volume of 258 skittles:
Volume of 258 skittles = 12 × 3 × 3 = 108 cm³
Volume of 1 skittle = 108 / 258 = 0.42 cm³
We found that the volume of 1 skittle is equal to 0.42 cm³. Now we calculate the volume of the skittles jar:
volume of cylinder = π × radius² × height
volume of skittles jar = 3.14 × 3.5² × 11.5 = 442 cm³
Now we can calculate the number of skittles in the jar:
number of skittles in the jar = volume of the jar / skittle volume
number of skittles in the jar = 442 / 0.42 = 1052 which is close the C) 1059
Learn more about:
volume of cylinder
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