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3 years ago

Live image and video. tell me is you can see the image or not.

Mathematics

1 answer:

Lemur [1.5K]3 years ago

6 0

Answer:

I can see the image a little.

Step-by-step explanation:

145.23

one hundred forty-five and twenty-three hundredths

23.457

twenty three and four-hundred and fifty seven thousandths

I cant see this one... Tell me in the comments and I'll give you the answer

Five tenths

<u>Fractions </u>

2.35

47/20

.625

5/8

5.75

23/4

2.72

68/25

I cant see this one either... Again, put it in the comments and I'll tell you the answer

025

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Give one example of when you would. use the friendly numbers strategy to subtract .Explain why ?

lord [1]

Say you were solving 27 + 19. If you were planning on using the friendly numbers strategy, you'd look at the first <span>addend, 27, and determine that</span> the closest "friendly number" here is thirty, which you'd get by adding 3. From there, you can jump to the next friendly number, forty, by adding another 10. So far you'd've added 13, and you'd need another 6 for that too add up to 19, your second addend. After adding 3, 10, and 6 to 27, you'd find your sum, or "final answer"- 46.

I hope this was what you were looking for!

5 0

3 years ago

The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe

UNO [17]

Answer:

The shark are fed $\frac16 \ ton$ of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = $\frac{2}{15}\ ton$

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = $\frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton$

Total fish fed in whole day = $\frac12 \ ton$

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = $\frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}$

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = $\frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}$

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = $\frac{3-2}{6}=\frac16 \ ton$

Hence The shark are fed $\frac16 \ ton$ of fish during the night.

3 0

3 years ago

Find −315÷134. Write your answer as a mixed number in simplest form.

kipiarov [429]

Answer:

$-2\frac{47}{134}$

Step-by-step explanation:

$-2\frac{47}{134} = -\frac{315}{134}$

$134$ can go into $-315$ twice at the most, so doubling $134$ will give us $268$ , which leaves us with $47$ left over to reach 315, which is why $47$ is the numerator. The remainder is ALWAYS the numerator.