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3 years ago

15

You are preparing a solution of lithium bromide to use during an experiment. The experiment calls for 909.7 mL a 18 M solution.

How many moles of the solute must be used to achieve this?

1 answer:

Zielflug [23.3K]3 years ago

4 0

Answer:

16.37 moles of lithium bromide.

Explanation:

909.7 mL of 18 M

= .9097 L of 18 M solution of lithium bromide .

no of moles required = .9097 x 18

= 16.37 moles of lithium bromide.

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