At what temperature do KCl and NaCl have the same solubility?
1 answer:
Answer:
they have the same molar solubility at 44.5 degrees celsius
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PV=nRT
P = 85.0 x 10^3 Pa
T = 273 + 20 = 293 K
n = 2.0 moles
R = 8.314 m3. pa / mol .K
V = 2.0 x 293 x 8.314 / 85.0x10^3 = 0.195623529 m^3