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3 years ago

At what temperature do KCl and NaCl have the same solubility?

Chemistry

1 answer:

Serhud [2]3 years ago

5 0

Answer:

they have the same molar solubility at 44.5 degrees celsius

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Which of the following is a characteristic of an S wave?

Soloha48 [4]

Answer:C) travel through solids and liquids

Explanation:

Though S waves can travel through solids, they cannot travel through liquids.

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3 0

3 years ago

. Calculate the final Celsius temperature of sulfur dioxide gas if 50.0 mL of the gas at 20 C and 0.450 atm is heated until the

Anna [14]

Answer:

The final temperature of sulfur dioxide gas is 215.43 C

Explanation:

Gay Lussac's Law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that if the temperature increases the pressure increases, while if the temperature decreases the pressure decreases. In other words, the pressure and temperature are directly proportional quantities.

Mathematically, the Gay-Lussac law states that, when a gas undergoes a transformation at constant volume, the quotient of the pressure exerted by the temperature of the gas remains constant:

$\frac{P}{T}=k$

Assuming you have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment, by varying the temperature to a new value T2, then the pressure will change to P2, and it will be true:

$\frac{P1}{T1} =\frac{P2}{T2}$

The reference temperature is the absolute temperature (in degrees Kelvin)

In this case:

P1= 0.450 atm
T1= 20 C= 293.15 K (being 0 C= 273.15 K)
P2=0.750 atm
T2= ?

Replacing:

$\frac{0.450atm}{293.15 K} =\frac{0.750 atm}{T2}$

Solving:

$T2 =\frac{0.750 atm}{\frac{0.450atm}{293.15 K} }$

$T2=\frac{0.750 atm}{0.450 atm} *293.15K$

T2=488.58 K

Being 273.15 K= 0 C, then 488.58 K= 215.43 C

<u><em>The final temperature of sulfur dioxide gas is 215.43 C</em></u>

6 0

3 years ago

Yo yuh guys know this

erastovalidia [21]

Answer:80KM is distance. 30KM north is displacement.

Explanation:

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3 years ago

The weather in an area is affected mostly by interactions between what elements?

AlexFokin [52]

Answer:B

Explanation:

4 0

3 years ago

When 2.50 g of an unknown weak acid (ha) with a molar mass of 85.0 g/mol is dissolved in 250.0 g of water, the freezing point of

baherus [9]

When dT = Kf * molality * i
= Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
= 2.5g /250g x 1 mol /85 g x1000g/kg
=0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
= (0.1176 * 0.359)^2 / (1-0.359)
= 2.8x10^-3

5 0

3 years ago