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sveticcg [70]
3 years ago
11

How many grams are in 8.3 moles of CaCl2?

Chemistry
2 answers:
ser-zykov [4K]3 years ago
8 0

Answer:

\Large \boxed{\sf 921.3 \ g}

Explanation:

Use formula

\displaystyle moles=\frac{mass}{M_r}

M_r=40+35.5 \times 2 = 111

Solve for mass

mass=8.3 \times 111=921.3

r-ruslan [8.4K]3 years ago
3 0

Answer:

(8.3×40)+(8.3×71)

921.3grames

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The nonvolatile, nonelectrolyte cholesterol, C27H46O (386.60 g/mol), is soluble in benzene C6H6. Calculate the osmotic pressure
soldier1979 [14.2K]

Answer:

Explanation:the formula for osmotic pressure is given in the first line, all the terms are explained before solution, from the question,

Molar mass=Mm=386.6

Mass= m= 14.6

Volume= 263/1000 = 0.263dm^3

Temperature=T= 298K.

Gas constant .R= 0.082

Then substitute into the equation πV= nRT

Making π subject of formula

π= nRT/V

Then further substitution

7 0
3 years ago
How many moles of iron can be recovered from 100.0 kg fe3o4?
Leokris [45]
Hello!

To know how many moles of iron can be recovered from 100 kg of Fe₃O₄ we'll need to use the molar mass of Fe₃O₄ and apply the conversion factor to go from kg of Fe₃O₄ to moles of Fe in the following way:

100 kg Fe_3O_4* \frac{1000 g}{1 kg}* \frac{1 mol Fe_3O_4}{231,533 g Fe_3O_4}* \frac{3 mol Fe}{1 mol Fe_3O_4}=1192,68 moles Fe

So, theoretically, one could recover 1192,68 moles of Fe from 100 kg of Fe₃O₄

Have a nice day!


5 0
3 years ago
Read 2 more answers
An aqueous solution of sodium hydroxide is standardized by titration with a 0.170 M solution of perchloric acid. If 28.5 mL of b
Ray Of Light [21]

Answer:

0.095M

Explanation:

HClO4 + NaOH = NaClO4 + H2O

Concentration of acid CA= 0.170M

Concentration of base CB= ???

Volume of base VB= 28.5ml

Volume of acid VA= 16.0ml

Number of moles of acid nA= 1

Number of moles of base nB= 1

From

CAVA/CBVB= nA/nB

CB= CAVAnB/VBnA

CB= 0.170×16.0×1/28.5×1

CB= 0.095M

4 0
3 years ago
What is the Anion and it’s charge.
Dafna11 [192]

Answer:

anion has a negative charge

An anion has more electrons than protons, consequently giving it a net negative charge

8 0
3 years ago
Calculate the mole fraction of the total ions in an aqueous solution prepared by dissolving 0.400 moles of CaI2 in 850.0 g of wa
Evgesh-ka [11]

Answer:

0.00840

Explanation:

The computation of the mole fraction is as follow:

As we know that

Molar mass = Number of grams ÷ number of moles

Or

number of moles = Number of grams ÷ molar mass

Given that

Number of moles of CaI2 = 0.400

And, Molar mass of water = 18.0 g/mol

Now  Number of moles of water is

= 850.0 g ÷ 18.0 g/mol

= 47.22 mol

And, Total number of moles is

= 0.400 + 47.22

= 47.62

So, Molar fraction of CaI2 is

= 0.400 ÷ 47.62

= 0.00840

4 0
3 years ago
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