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3 years ago

How many grams are in 8.3 moles of CaCl2?

Chemistry

2 answers:

ser-zykov [4K]3 years ago

8 0

Answer:

$\Large \boxed{\sf 921.3 \ g}$

Explanation:

Use formula

$\displaystyle moles=\frac{mass}{M_r}$

$M_r=40+35.5 \times 2 = 111$

Solve for mass

$mass=8.3 \times 111=921.3$

r-ruslan [8.4K]3 years ago

3 0

Answer:

(8.3×40)+(8.3×71)

921.3grames

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Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value. (6.0 x 1

Greeley [361]

I believe the correct answer from the choices listed above is the second option. The expression (6.0 x 104) (3.1 x 10-1) is equal to 1.9 x 10^4. We only have two significant figures from the starting expression that is why we rounded of the product from 1.86 to 1.9.

3 0

3 years ago

What is the coordination number for each of the following complexes or compounds? [Co(NH3)4(H2O)2]3+ [Cr(EDTA)]− [Pt(NH3)4]2+ Na

Burka [1]

Answer:

[Co(NH₃)₄(H₂O)₂]³⁺: coordination number = 6.

[Cr(EDTA)]⁻: coordination number = 6.

[Pt(NH₃)₄]²⁺: coordination number = 4.

Na[Au(Cl)₂]: coordination number = 2.

Explanation:

[Co(NH₃)₄(H₂O)₂]³⁺:

In this complex, Co is bonded with 4 molecules of NH₃ (with 4 coordinate bonds, one bond for each molecule) and 2 molecules of H₂O (with 2 coordinate bonds, one bond for each molecule) forming the complex with 6 coordinate bonds.

∴ coordination number = 6.

[Cr(EDTA)]⁻:

In this complex, Cr is bonded with 1 molecules of EDTA (with 6 coordinate bonds, 4 O atoms and 2 N atoms in EDTA molecule).

∴ coordination number = 6.

[Pt(NH₃)₄]²⁺:

In this complex, Pt is bonded with 4 molecules of NH₃ (with 4 coordinate bonds, one bond for each molecule).

coordination number = 4.

Na[Au(Cl)₂]:

In this complex, Au is bonded with 2 atoms of Cl (with 2 coordinate bonds, one bond for each atom).

coordination number = 2.

3 0

3 years ago

Which of the following is an oxide which is strongly acidic?

borishaifa [10]

Answer:

answer of your question is 4th

Explanation:

P205

3 0

3 years ago

What is the mass of 2.70 ×10^22 molecules of NaOH (Molar mass = 40.0 g/mol)?

Viefleur [7K]

Data:
Molar Mass of NaOH = 40 g/mol

Solving: <span>According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
</span>
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules

6.02*10²³y = 0.270*10²³
$y = \frac{0.270*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}{6.02*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}$
$\boxed{y \approx 0.04\:mol}$

Solving: <span>Find the mass value now
</span>
40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH

$x = 40*0.04$
$\boxed{\boxed{x = 1.6\:g}}\end{array}}\qquad\quad\checkmark$

Answer:
The mass is 1.6 grams

6 0

3 years ago

24 g of magnesium were burned in oxygen. The compound formed had a mass of 40 g. Explain why the mass had gone up.

DIA [1.3K]

Answer :

According to the law of conservation of mass, the mass of reactants must be equal to the mass of products.

The balanced chemical reaction is,

$Mg+\frac{1}{2}O_2\rightarrow MgO$

As we know that the molar mass of magnesium is 24 g/mole, the molar mass of $O_2$ is 32 g/mole and the molar mass of magnesium oxide is 40 g/mole.

From the given balanced reaction, we conclude that

As, 1 mole of magnesium react $\frac{1}{2}$ mole of oxygen to give 1 mole of magnesium oxide.

So, the mass of Mg is 24 g, the mass of $O_2=\frac{1}{2}\times 32=16g$ and the mass of MgO is 40 g.

That means 24 g of Mg react with 16 g $O_2$ to give 40 g of MgO.

8 0

3 years ago