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Sliva [168]
3 years ago
14

Please help, thank you!

Mathematics
1 answer:
mezya [45]3 years ago
4 0

Answer:

Triangle OBA is a right angled triangle since a radius meets a tangent at an angle of 90°..So use pythogrus theorem to find the radius.

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The table below shows the data for a random sample of fish that were collected from and later released into a lake: Catfish-52 G
castortr0y [4]
208 is the answer
add all the numbers multiply till 800
multiply 52 by the same number and you'll get the answer

6 0
3 years ago
Read 2 more answers
A box of fruit has four times more peaches than plums.
Ugo [173]

Answer:

The number of plums = 4

The number of peaches =  16

The number of nectarines =  1

Step-by-step explanation:

Let the number of peaches be = x

Let the number of nectarines be = y

Let the number of plums be = z

A box of fruit has four times more peaches than plums. This means that

The number of peaches = 4 X the number of plums.

i.e x = 4z

The box has 3 fewer nectarines than plums. This means that

Number of nectarines = number of plums - 3

i.e y = z - 3

If the box contains 21 pieces of fruit, this means that if we sum up all the peaches, nectarines, and plums in the box, we will get 21.

Peaches + Nectarines + Plums = 21

4z + z-3 + z = 21

6z =21 +3

z = 24/6

z = 4

Therefore, the number of plums = 4

The number of peaches = 4 X 4 = 16

The number of nectarines = 4 -3 = 1

7 0
3 years ago
What's the product of (1/3x^2y)*(1/6xy^3)
leonid [27]

Answer: \frac{1}{18x^3y^4}

5 0
2 years ago
1)cot a/2 -tan a/2 = 2 cot a<br>2) cot b/2 + tan b/2= 2 cosec b<br> prove​
VladimirAG [237]
1)

LHS = cot(a/2) - tan(a/2)

= (1 - tan^2(a/2))/tan(a/2)

= (2-sec^2(a/2))/tan(a/2)

= 2cot(a/2) - cosec(a/2)sec(a/2)

= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))

= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)

= 2[(1+cos(a) -1)/sin(a)]

=2cot a

= RHS

2.

LHS = cot(b/2) + tan(b/2)

= [1 + tan^2(b/2)]/tan(b/2)

= sec^2(b/2)/tan(b/2)

= 1/sin(b/2)cos(b/2)

using product to sums

= 2/sin(b)

= 2cosec(b)

= RHS
8 0
3 years ago
(Another Question from meh since Imma dum kid) How do you know when you can stop looking for factors of a number?
alina1380 [7]

stop? STOP??? WHEN U WANT TO HAHAHAHA

4 0
3 years ago
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