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2 years ago

Which shows the equation in point-slope form of the line passing through the given point with the given slope?

Mathematics

1 answer:

avanturin [10]2 years ago

3 0

<h2>SOLVING</h2>

$\Large\maltese\underline{\textsf{A. What is Asked}}$

Find the point-slope equation of the line, with the info given

$\Large\maltese\underline{\textsf{This problem has been solved}}$

Formula used, $\bf y-y1=m(x-x1)$

$\bf y-5=13(x-0)}$ | result

$\rule{300}{1.7}$

$\boxed{\bf aesthetic\not101}}$

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4. In a sample of 1000 people, 130 can wiggle their ears. Two unrelated people are

Elina [12.6K]

Using the hypergeometric distribution, it is found that there is a 0.7568 = 75.68% probability that neither can wiggle his or her ears.

The people are chosen from the sample without replacement, which is why the <u>hypergeometric distribution</u> is used to solve this question.

Hypergeometric distribution:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.

In this problem:

1000 people means that $N = 1000$
130 can wiggle their ears, thus $k = 130$
Two are selected, thus $n = 2$ .

The probability that neither can wiggle his or her ears is P(X = 0), thus:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = x) = h(0,1000,2,130) = \frac{C_{130,0}C_{870,2}}{C_{1000,2}} = 0.7568$

0.7568 = 75.68% probability that neither can wiggle his or her ears.

A similar problem is given at brainly.com/question/24826394

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2 years ago

Solve for x.<br><br> 2(4x− 9) = 5(x − 4)

cluponka [151]

Answer:

2(4x− 9) = 5(x − 4)

=>8x- 18= 5x-20

=>8x-5x= -20+18

=>3x = -2

=>x= -2/3

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3 years ago

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Veseljchak [2.6K]

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3 years ago

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How does your figure look like?

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3 years ago

Read 2 more answers

9 (1/3)^n-1 what is the tenth term

NARA [144]

Answer:

$a_{10}=\frac{1}{2187}$

Step-by-step explanation:

Simply plug in 10 for <em>n</em>

9(1/3)¹⁰⁻¹

9(1/3)⁹

9(1/19683)

9/19683

$a_{10}=\frac{1}{2187}$

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3 years ago