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Semmy [17]
4 years ago
12

Please help me with this logs question!

Mathematics
1 answer:
Temka [501]4 years ago
6 0
no1 is the answer......
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For three minutes the temperature of a feverish person has had negative first derivative and positive second derivative.
nydimaria [60]

Answer:

A.) The temperature fell in the last minute, but less than it fell in the minute before.

Step-by-step explanation:

Given that for three minutes the temperature of a feverish person has had negative first derivative and positive second derivative.

i.e. it temperature is represented by T, temperature is variable with

first derivative T' <0 and second derivative T">0

i.e. rate of change of temperature is negative or temperature is falling down in 3 minutes.

But the rate of rate of change of temperature was positive i.e. the rate of change of temperature is increasing as time increases.

So correct option would be option A

A.) The temperature fell in the last minute, but less than it fell in the minute before.

7 0
4 years ago
Which is 625 written as a power of 5 (exponets) A. 4*5 B.3*5 C.5*3 D.5*4
OleMash [197]
<span>625 written as a power of 5 = 5^4
because
5^4 = (5) * (5) *(5) * (5)  =625

answer is
</span><span>D.5^4</span>
8 0
3 years ago
Read 2 more answers
A drawer has 5 red socks and 5 socks.  If 3 drawn what is the probability that they are a match?
Lilit [14]
Since there are only 2different colors of socks by tge tgird draw you are guaranteed to have a match so 100%
3 0
4 years ago
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What is the domain of the function g(x)=3log2(x−1)+4 ? <br> All real numbers greater than ___
lorasvet [3.4K]

<u>Answer-</u>

<em>The domain of g(x)=3\log 2(x-1)+4 is, </em>

<em>\boxed{\boxed{(x:x\ \epsilon\ R\ and\ R>1)}}</em>

<u>Solution-</u>

For y=\log x, there can not have a log to any value of x, which is either negative or 0.

So domain of log x is,

(x:x\ \epsilon\ R\ and\ R>0)

Equating 2(x-1) to 0, we can get the domain of the given function, hence

\Rightarrow 2(x-1)>0\\\\\Rightarrow x-1>0\\\\\Rightarrow x>1

Therefore, domain of g(x) is any real number greater than 1, i.e

(x:x\ \epsilon\ R\ and\ R>1)


3 0
4 years ago
Read 2 more answers
Please answer this correctly
Andrews [41]

Answer:

2 minutes 56 seconds

Step-by-step explanation:

3 0
4 years ago
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