2x^2-x+x^2-3x combine like terms
3x^2-4x set equal to zero and factor
x(3x-4)=0 solve each individual factor to find the solutions/roots
x=4/3, 0
Answer:
45° + x° = 90°
Step-by-step explanation:
Two angles are complementary if the sum of the angles is equal to 90 degrees. we can also said that if we had two angles A and B and these angles are complementary, the equation that represent this situation is:
A + B = 90°
Then, if a 45°angle is complementary to an angle measures ×°, the equation that represents this situation is:
45° + x° = 90°
Therefore, solving for x°, we get:
45° + x° - 45° = 90° - 45°
x° = 45°
it means that a 45°angle is complementary to an angle measures 45°
Answer: 110°
<u>Step-by-step explanation:</u>
∠A ≅ ∠B
since ∠A = 35° (given), then ∠B = 35°
Use the Triangle Sum Theorem to find ∠C:
∠A + ∠B + ∠Q = 180°
35° + 35° + ∠Q = 180°
70° + ∠Q = 180°
∠Q = 110°
The central angle (∠AQB) ≅ arc AB
since ∠AQB = 110° (solved above), then arc AB = 110°
58 because it couldn’t be 45 and 67 so it’s either 78 or 58 but since i need some points i’m acting like i know the answer