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3 years ago

14

Q # 20 please help to solve

1 answer:

spin [16.1K]3 years ago

8 0

If submarine is at the surface (the initial position) and then dives 375 ft, the coordinate of submarine becomes -375 ft <span>relatively to the initial position. When the submarine dives another 175 ft down, the coordinate of submarine becomes -375-175=-550 ft relatively to the initial position.
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Answer: Correct choice is A.
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If George received $78.00 for his work and he gets paid 6 dollars and hour how much is he getting paid

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What is 2% out of 3000

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3. Solve using substitution.<br> x - y = 4<br> 3x - 2y = -5

Vedmedyk [2.9K]

<u>Given</u>:

The system of linear equations are $x-y=4$ and $3x-2y=-5$

We need to determine the solution to the system of equations using substitution method.

<u>Solution</u>:

The solution can be determined using the substitution method.

Let us substitute $x=4+y$ in the equation $3x-2y=-5$

Thus, we have;

$3(4+y)-2y=-5$

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3 years ago

Mr. Nelson bought a car for $20,000 with a 5% interest rate.

LekaFEV [45]

Answer:

A ) Hence The interest for the car loan is $ 4,310

B ) Hence The interest for the car loan is $ 3,152

Step-by-step explanation:

Given as :

The loan for the car = $ 20,000

The rate of interest of car loan = 5 % compounded annually

A ) The period of loan = 48 months = 4 years

Let the interest of the loan = CI

<u>From compounded method</u>

Amount = Principal × $(1 + \frac{\textrm Rate}{100})^{\textrm time}$

Or, Amount = $ 20,000 × $(1 + \frac{\textrm 5}{100})^{\textrm 4}$

Or, Amount = $ 20,000 × $(1.05)^{4}$

Or, Amount = $ 20,000 × 1.2155

∴ Amount = $ 24310

So, Interest = Amount - Principal

Or, CI = $ 24,310 - $ 20,000

∴ CI = $ 4,310

Hence The interest for the car loan is $ 4,310

B ) The loan for the car = $ 20,000

The rate of interest of car loan = 5 % compounded annually

The period of loan = 3 years

Let the interest of the loan = CI

So,

<u>From compounded method</u>

Amount = Principal × $(1 + \frac{\textrm Rate}{100})^{\textrm time}$

Or, Amount = $ 20,000 × $(1 + \frac{\textrm 5}{100})^{\textrm 3}$

Or, Amount = $ 20,000 × $(1.05)^{3}$

Or, Amount = $ 20,000 × 1.1576

∴ Amount = $ 23,152

So, Interest = Amount - Principal

Or, CI = $ 23,152 - $ 20,000

∴ CI = $ 3,152

Hence The interest for the car loan is $ 3,152

6 0

4 years ago