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2 years ago

30 students in a class went on a trip to the other side of the city. There were 4 vans for the

Mathematics

1 answer:

torisob [31]2 years ago

3 0

Answer:

Step-by-step explanation:

30-6=24

(6 people walked which means they are not included in the people fitting on the busses)

24/4=6

(from there you need to divide by 4 to tell how many were on each bus.)

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nalin [4]

Answer:

No similarity and no scale factor (I could be wrong)

Step-by-step explanation:

Don't worry, no links :)

You would see if they are similar if they have similar sides. so if there is an equal ratio, to both, they are similar. Sometimes they may not look similar until you rotate them. So for the following, you can see that if E were on the bottom, it would look like the triangle with N and M on the bottom you can ensure this to look at the ratios of each side. To find the scale factor, it depends on which way you are going. are you going from GEF to MNL or MNL to GEF? To me, it doesn't look like there is a scale factor, but I could be wrong.

8 0

3 years ago

. 40% of 60 students of a class are good at art. How many students are not good at art? *

melisa1 [442]

Answer:

Step-by-step explanation:

1-40% = 1-0.4=0.6 or 60%

60% not good at art.

60*60% = 60*6/10 = 6*6 = 36

6 0

1 year ago

Read 2 more answers

What is Factorise 5x+20

Stolb23 [73]

5x + 20
5(x) + 5(4)
5(x + 4)

8 0

3 years ago

Read 2 more answers

What is 0.561 rounded to the nearest tenth

garri49 [273]

The answer would be 0.6. hope that helped

4 0

3 years ago

Read 2 more answers

amirah ,who is at a point P ,observes a boat at pont B 1200m from P in direction 047 degrees. The boat is moving due north of B

Luda [366]

Answer:

about 2.81 km/h

Step-by-step explanation:

It can be useful to draw a diagram.

The lines pointing to due north from points B and P are parallel, so the angle BCP and the bearing of point C from P are the same, 30°. The angle BPC will be the difference of bearings of B and C at P, so is 47-30=17°. This is enough information to solve the triangle using the Law of Sines:

PB/sin(C) = CB/sin(P)

CB = PB·sin(P)/sin(C) = (1200 m)·sin(17°)/sin(30°) ≈ 701.7 m

The speed of the boat is then ...

x = distance/time = (0.7017 km)/(1/4 h) = 2.8068 km/h

6 0

3 years ago